...left-hand period ; place its root in the quotient, and fubtraft the number itfelf from faid lefthand period ; and to the remainder annex the next period for a dividend. Write the* double of the part of the root found on the left-hand of the dividend, which divide by it,...

...the right hand of the given number, as in division. Subtract the square of this root from the first period ;and to the remainder, annex the next period, for a dividend. Double the root already found, and place it to the left hand of the dividend. Consider, what figure can be annexed...

...contained in it, if it be not a cute tUelf. (3.) Subtract the third power of this figure from the first period, and to the remainder annex the next period for a dividend, and for part of the divisor take 300 times the square of the part of the root already obtained. ^.)...

...rwd, and to the remainder annex the second period; the result will be the FIRST DIVIDEND. //I. Double the root already found, and place it on the. left of the number, for the FIRST TRIAL DIVISOR. See how many times this trial divisor, with a cipher annexed,...

...the greatest cube in the left-hand period, put its root in the quotient, subtract the cube from that period, and to the remainder annex the next period for a dividend. Multiply the square of the root by 300 for a divisor, and take it out of the dividend, the quotient...

...which write in the quotient or root, and the square thereof under the same period ; subtract therefrom, and to the remainder annex the next period for a dividend. Double the quotient for a divisor ; see how often the divisor is contained in the dividend, with this consideration,...

...to the right of the remainder bring down the next period for a dividend. III. Double the root just found and place it on the left of the dividend for a partial divisor, find how many times it is contained in the dividend, omitting its right hand figure...

...to the right of the remainder bring down the next period for a dividend. III. Double the root just found and place it on the left of the dividend for a partial divisor; find how many times M is contained in the dividend, omitting its right hand figure...

...period, enter it under the period, and its root in the quotient place, tahe this 3rd power from the period, and to the remainder annex the next period for a dividend. III. Divide this dividend, omitting the last two figures, by three times the 2nd power of the figure...

...to the right of the remainder bring down the next period for a dividend. III. Double the root just found and place it on the left of the dividend for a partial divisor, find how many timesit is contained in the dividend, omitting its right hand figure...