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" RULE.* Multiply the principal by the rate per cent, and divide the product by 100: the quotient will be the interest for 1 year. "
Arithmetic. [With] Key - Página 196
por Robert Goodacre - 1839
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A Treatise on Arithmetic

J. Brookes - 1776 - 364 páginas
...forbearance of any fum of money, for fome determined fpace of time. RULE I. When the Intereft is required for a Year, multiply the Principal by the rate per Cent, and divide that Product by loo, the Quotient is the Intercft required. What's the Intereft of 1 79/. for a Year,...
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A New System of Mercantile Arithmetic: Adapted to the Commerce of the United ...

Michael Walsh - 1807 - 290 páginas
...is the sum per cent.-agreed on. Amount, is the principal and interest added together. GENERAL RULE. Multiply the principal by the rate per cent, and divide the product by 100, and the quotient is the answer for one year.. EXAMPLES. 1 . What is the interest of ¿£.496 for one...
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A New and Plain System of Arithmetic: Containing the Several Rules of that ...

Elijah H. Hendrick - 1810 - 220 páginas
...Simple and Compound.!, SIMPLE INTEREST is that which arifes from the principal only. General Rule. I. Multiply the principal by the rate per cent, and divide the product by loo, (or, which is the fame, cut-off two right hand figures in the pounds, which mint be reduced to...
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The Teachers Assistant. Or, A System of Practical Arithmetic: Wherein the ...

1811 - 210 páginas
...CASE*1!. When the time is one year, and the rate per cent, is pounds or dollars only. * • RULE.» Multiply the principal by the rate per cent, and divide the product by 100. PROOF. , , By the Single Rule of Three. EXAMPLES. 1. What is the interest of 525 L. for 1 year, at...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1815 - 250 páginas
...principal and interest added together. CASE I. To find the interest of any given sum for one year. RULE. Multiply the principal by the rate per cent, and divide the product by 100 ; the quotient will be the answer. EXAMPLE!. 1. What is the interest of 39Z. lls. 8id. for one year at 61. per cent,...
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The New American Arithmetic, in the Coin of the United States, Denominated ...

John Lyman Newell - 1822 - 222 páginas
...When the interest of any sum is required for one year, how do you proceed ? A. In finding the interest for a year, multiply the principal by the rate per cent., and remove the separatrix from its natural place two figures towards the left hand, then all those figures...
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Daboll's Schoolmaster's Assistant, Improved and Enlarged: Eing a Plain ...

Nathan Daboll - 1823 - 262 páginas
...principal and interest added together. CASE I. To find the interest of any given sum for one yeai» RULE. Multiply the principal by the rate per cent. and divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of S9/. Us. 8itI. for one year, at 61. per cent....
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The Teachers' Assistant: Or a System of Practical Arithmetic

Stephen Pike - 1824 - 212 páginas
...1. To find the interest when the time is one year, and the rate per cent. is pounds or dollars only. Multiply the principal by the rate per cent. and divide the product by 100: the quotient will be the interest for 1 year. PROOF. By the Single Rule of Three. EXAMPLES. 1. What is the interest...
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Daboll's Schoolmaster's Assistant, Improved and Enlarged

Nathan Daboll - 1825 - 248 páginas
...principal and interest addeâ together. CASE i. Vb find {he interest of any given sum for one ysar. RULE. Multiply the principal by the rate per cent. and divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of 391. 11s. SJd. for one year. at 61. per cent,...
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Pike's System of Arithmetic Abridged: To which are Added Appropriate ...

Nicolas Pike, Dudley Leavitt - 1826 - 214 páginas
...insurance of his property, and is generally at so much per cent. RULE. — Multiply the sum to be insured by the rate per cent. and divide the product by 100 ; — the quotient will be the premium or answer. EXAMPLE. What will be the annual premium for insuring a house against...
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