...sum of the three sides, subtract each side severally; multiply the half sum and the three remainders together, and the square root of the product will be the area required. EXAMPLE I. Rcquireth the area of a triangle ABC, whose three sides AB, BC, and CA, are respectively...

...of the three sides, subtract each side severally ¡ multiply the half sum and the three remainders together, and the square root of the product will be the area required. Едг. Requireth the area of a triangle ABC, whose three »ides AB BC, and CA, are respectively...

...each side from that half sum ; then multiply the said half sum and the three remainders continually together ; and the square root of the product will be the area of the triangle. EXAMPLES. 1. — Required the area of the triangular field ABC, whose base AB is 650,...

...— c2) X (c2— a— 56 MENSURATION 2. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. EXAMPLES. 1. Required the area of the triangle ABC, whose three sides BC, CA, and AB are...

...sides, subtract each side separately, and multiply the half sum and the three remainders continually together; and the square root of the product will be the area. the sides Then by hence AD r: — E 1C, geAC, and AB, t» — «' "~~ 2 с ¿> — ; o AD —DB = —...

...the sum of the sides subtract each side separately. Multiply the half sum and the several remainders together, and the square root of the product will be the area. — ED . her corresponding to one half the sum of those logarithms will be the area of the triangle....

...subtract each side separately ; then multiply the said half sum and the three remainders continually together, and the square root of the product will be the area of the triangle. Ex. 1. What is the area of a triangle whose base is 15 feet, and perpendicular height...

...three sides subtract each side severally. 2. Multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. RULE. ii. Any two sides of a triangle being multiplied together, and the product again by...

...sides subtract each side several! y, then multiply the half sum and the three remainders continually together, and the square root of the product will be the area required. AN EXAMPLE. In the triangle ABC let the side AC be 40 poles, CB50, and AB 60 ; required,...

...its height. , RULE. Multiply the base by / e height, and § of the product c _ — the height, and § of the product will be the area.* 1. Required the area of a parabola, whose height is 6 and base 12? , 6 X 12 X § = 48 the area. 2. What is the area of a parabola,...