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" RULE.* Multiply the principal by the rate per cent, and divide the product by 100: the quotient will be the interest for 1 year. "
The Teachers' Assistant, Or, A System of Practical Arithmetic: Wherein the ... - Página 79
1847 - 198 páginas
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A New System of Mercantile Arithmetic: Adapted to the Commerce of the United ...

Michael Walsh - 1801 - 268 páginas
...Rate, is the fum per cent, agreed on. * Amona t, is the principal and intereft added together. GENERAL RULE. Multiply the principal by the rate per cent. and divide the product by 100, and the quotient is the anfwer for one year,' EXAMPLES. i. What is the intereft of ¿".496 for one...
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A New System of Mercantile Arithmetic: Adapted to the Commerce of the United ...

Michael Walsh - 1801 - 292 páginas
...Rait, is the fum per cent. agreed on. Amount. is the principal and interefl added together. GENERAL RULE. Multiply the principal by the rate per cent. and divide the prodacl by ijcSl and the quotient is the anlv/cr for one year, EXAMPLES. 1. What is the intereft of...
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The American Tutor's Assistant Revised, Or, A Compendious System of ...

Zachariah Jess - 1810 - 222 páginas
...arises from tta principal only. CASE 1. When tfcfc time is any number of years, asd the rate per cent, pounds or dollars only ; RULE. Multiply the principal by the rate per cent, and divide the produél by 1 00, the quotient will be the interest for one year ; which multiply by the years given....
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A New and Plain System of Arithmetic: Containing the Several Rules of that ...

Elijah H. Hendrick - 1810 - 220 páginas
...Simple and CotnpoUnd.l SIMPLE INTEREST is that which arifes from the principal only. General Rule. 1. Multiply the principal by the rate "per cent, and divide the product by loo, (or, which is the fame, cut. off two right hand figures in the pounds, which muit be reduced to...
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The Teachers Assistant. Or, A System of Practical Arithmetic: Wherein the ...

1811 - 210 páginas
...dollars, for one- year. Fourth. The amount, which is the sum of the principal and interest. CASE^l. When the time is one year, and the rate per cent, is pounds...the rate per cent, and divide the product by 100. PROOF. By the Single Rule of Three. EXAMPLES. 1. What is the interest of 525 L. for 1 year, at 6L....
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Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1815 - 250 páginas
...principal and interest added together. CASE I. To find the interest of any given sum for one year. RULE. Multiply the principal by the rate per cent,...divide the product by 100 ; the quotient will be the answer. EXAMPLE!. 1. What is the interest of 39Z. lls. 8id. for one year at 61. per cent, per annum...
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The Teachers' Assistant, Or, A System of Practical Arithmetic: Wherein the ...

1817 - 214 páginas
...which interest is to be calculated. The amount is the sum of the principal and interest. CASE 1. 'iVhen the time is one year, and the rate per' cent, is pounds or dollars only. RULE. * Multiply the principality the rate percent, and divide the product by 100 : the quotient will be the interest for...
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Daboll's Schoolmaster's Assistant, Improved and Enlarged: Eing a Plain ...

Nathan Daboll - 1823 - 262 páginas
...principal and interest added together. CASE I. To find the interest of any given sum for one yeai» RULE. Multiply the principal by the rate per cent....divide the product by 100 ; the quotient will be the answer. EXAMPLES. 1. What is the interest of S9/. Us. 8itI. for one year, at 61. per cent. per annum...
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The Teachers' Assistant: Or a System of Practical Arithmetic

Stephen Pike - 1824 - 212 páginas
...calculated. The amount is the sum of the principal and interest. CASE 1. To find the interest when the time is one year, and the rate per cent. is pounds...* Multiply the principal by the rate per cent. and dl vide the product by 100: the quotient will be the in. terest for 1 year. PROOF. By the Single Rule...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged. Being a Plain ...

Nathan Daboll - 1824 - 264 páginas
...principal and interest added together • CASE I. To find the interest of any given sum for one year. RULE. Multiply the principal by the rate per cent. and divide the product by 100} the quotient \vill be the answer. EXAMPLES. 1. What is the interest of 391. lls. 8Jd. for one year at 6/. per cent...
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