 | Timothy Walker - 1829 - 156 páginas
...the remainder. 183. By applying the above rules, the following questions will be readily answered. 1. How long must a ladder be to reach the top of a wall 60 feet high, the foot of the ladder being 12 feet from the wall ? 2. A prop 30 feet long has... | |
 | Timothy Walker - 1829 - 138 páginas
...— . 183. By applying the above rules, the following ques- /£^t<) tions will be readily answered. 1. How long must a ladder be to reach the top of af~l wall 50 feet high, the foot of the ladder being 12 feet from the wall f 2. A prop 30 feet long... | |
 | George Hutton (arithmetic master, King's coll. sch.) - 1844 - 276 páginas
...of 18 feet from the base of a building to support a jamb 24 feet from the ground ? Ans. 30 feet. 12. How long must a ladder be to reach the top of a wall, 41 feet 3 inches in height from the surface of a river 23 yds. 1 foot in breadth, which flows... | |
 | George Roberts Perkins - 1846 - 266 páginas
...being given, the third side can be found. EXAMPLES. 1. How long must a ladder be, to reach to the^top of a house 40 feet high, when the foot of it is 30 f$et from the house ' In this example, it is obvious that the ladder forms the hypotenuse of a right-angled... | |
 | George Roberts Perkins - 1849 - 356 páginas
...square of the other side. By means of these properties, when two sides of a right-angled triangle are given, the third side can be found. EXAMPLES. 1. How...this example, it is obvious that the ladder forms the hypothenuse of a right-angled triangle, whose sides are 30 and 40 feet, respectively. Therefore, the... | |
 | George Roberts Perkins - 1850 - 364 páginas
...triangle being given, the third side can be found. EXAMPLES. 1. How long must a ladder be, to reach to the top of a house 40 feet high, when the foot of...ladder must equal the sum of the squares of 30 and 40. 302=: 900 40^ = 1600 -V/25 )0 = 50, the length of the ladder. 2. Suppose a ladder 100 feet long, to... | |
 | George Roberts Perkins - 1850 - 356 páginas
...square of the other side. By means of these properties, when two sides of a right-angled triangle are given, the third side can be found. EXAMPLES. 1. How...this example, it is obvious that the ladder forms the hypothenuse of a right-angled triangle, whose sides are 30 and 40 feet, respectively. Therefore, the... | |
 | George Roberts Perkins - 1855 - 388 páginas
...triangle being given, the third side can be found. EXAMPLES. 1. How long must a ladder be, to reach to the top of a house 40 feet high, when the foot of...this example, it is obvious that the ladder forms ths hypotenuse of a right-angled triangle, whose sides are 30 and 40 feet respectively. Therefore,... | |
 | George Roberts Perkins - 1865 - 360 páginas
...triangle being given, the third side can be found. EXAMPLES. 1. How long must a ladder be, to reach to the top of a house 40 feet high, when the foot of...this example, it is obvious that the ladder forms tha hypotenuse of a right-angled triangle, whose sides are 30 and 40 feet respectively. Therefore,... | |
 | Ohio. Department of Education - 1876 - 386 páginas
...of cloth, Ц yards wide, to clothe 220 men, how many yards, .V4 wide, will it take for 121 men ? 10. How long m,ust a ladder be to reach the top of a tree 80 feet high, when the foot of it is ti0 feet from the tree ? ORTHOGRAPHY. 1 . Of what does orthography... | |
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From the above proposition, it follows that the square of the hypotenuse, diminished by the square of one of the sides, equals the square of the other side. By means of these properties, it follows that two sides of a right-angled triangle being given,... 
