Spherical Trigonometry ...Macmillian and Company, limited, 1859 - 275 páginas |
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Página 28
... remaining two formulæ of Art . 39 will shew that B and C are the same in the two triangles . It should be observed that the two triangles in this case are not necessarily such that one may be made to coincide with the other by ...
... remaining two formulæ of Art . 39 will shew that B and C are the same in the two triangles . It should be observed that the two triangles in this case are not necessarily such that one may be made to coincide with the other by ...
Página 30
... remaining side is the supplement of the remaining angle ; or else that the triangle has two quadrants and two right angles , and then the remaining side is equal to the remaining angle . α A 2 = 6. In an equilateral triangle , 30 ...
... remaining side is the supplement of the remaining angle ; or else that the triangle has two quadrants and two right angles , and then the remaining side is equal to the remaining angle . α A 2 = 6. In an equilateral triangle , 30 ...
Página 32
... remaining elements . It will appear , as we proceed , that when the values of three of the elements are given , those of the remain- ing three can generally be found . We begin with the right - angled triangle ; here two elements , in ...
... remaining elements . It will appear , as we proceed , that when the values of three of the elements are given , those of the remain- ing three can generally be found . We begin with the right - angled triangle ; here two elements , in ...
Página 36
... remaining two parts are called opposite parts . For π example , if – B is selected as the middle part , then the adjacent 2 b π parts are a and 7 - c , and the opposite parts are 6 and 7 – 4 . 2 Then Napier's Rules are the following : 2 ...
... remaining two parts are called opposite parts . For π example , if – B is selected as the middle part , then the adjacent 2 b π parts are a and 7 - c , and the opposite parts are 6 and 7 – 4 . 2 Then Napier's Rules are the following : 2 ...
Página 38
... 2 2 - a , and the sides respectively opposite these angles equal Π to B and 2 П - C. The circular parts of AED are therefore the 1 same as those of ABC . Similarly the remaining three 38 . SOLUTION OF RIGHT - ANGLED TRIANGLES . H ...
... 2 2 - a , and the sides respectively opposite these angles equal Π to B and 2 П - C. The circular parts of AED are therefore the 1 same as those of ABC . Similarly the remaining three 38 . SOLUTION OF RIGHT - ANGLED TRIANGLES . H ...
Otras ediciones - Ver todas
Spherical Trigonometry: For the Use of Colleges and Schools Isaac Todhunter Vista de fragmentos - 1949 |
Spherical Trigonometry: For the Use of Colleges and Schools Isaac Todhunter Vista de fragmentos - 1929 |
Términos y frases comunes
A+B+C ambiguity angular points approximately bisecting Cambridge centre circular measure cloth cos b cos cos² cos³ cosine Crown 8vo deduce denote drawn equal angles equilateral example expressed Fcap formulæ formulæ of Art greater Hence hypothenuse inscribed Legendre's Theorem less Let ABC lune meet middle point Napier's analogies Napier's Rules obtained octahedron opposite angle opposite sides parallelopiped perpendicular plane angles plane triangle Plane Trigonometry polar triangle pole polygon preceding article primitive triangle prove quadrant R₁ r₂ radius regular polyhedron respectively right angle right-angled triangles Second Edition shew shewn sides and angles Similarly sin b cos sin b sin sin² sin³ sine solid angle sphere spherical excess spherical triangle Spherical Trigonometry subtended Suppose surface tangent tetrahedron Treatise triangle ABC Trigono Trinity College values π π
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Página 28 - If two triangles have two sides of the one equal to two sides of the...