Spherical Trigonometry ...Macmillian and Company, limited, 1859 - 275 páginas |
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... straight line which joins any point of the surface with the centre is called a radius . A straight line drawn through ... right angle ; therefore CD = √ ( OD3 – OC2 ) . Now O and C are fixed points , so that OC is constant ; and OD is ...
... straight line which joins any point of the surface with the centre is called a radius . A straight line drawn through ... right angle ; therefore CD = √ ( OD3 – OC2 ) . Now O and C are fixed points , so that OC is constant ; and OD is ...
Página 1
... straight line which joins any point of the surface with the centre is called a radius . A straight line drawn through the ... right angle ; therefore CD = √ ( OD- OC ) . Now O and C are fixed points , so that OC is constant ; and OD is ...
... straight line which joins any point of the surface with the centre is called a radius . A straight line drawn through the ... right angle ; therefore CD = √ ( OD- OC ) . Now O and C are fixed points , so that OC is constant ; and OD is ...
Página 4
... quad- rant and at right angles to ABC . For let O be the centre of the sphere , and draw PO . Then PO is at right angles to the plane ABC , because P is the pole of ABC , therefore POA is a right angle , and 4 GREAT AND SMALL CIRCLES .
... quad- rant and at right angles to ABC . For let O be the centre of the sphere , and draw PO . Then PO is at right angles to the plane ABC , because P is the pole of ABC , therefore POA is a right angle , and 4 GREAT AND SMALL CIRCLES .
Página 5
... right angles to the plane ABC , the angle between the planes POA and ABC is a right angle ; therefore the arc PA is at right angles to AC . 11. If the arcs of great circles joining a point P on the surface of a sphere with two other ...
... right angles to the plane ABC , the angle between the planes POA and ABC is a right angle ; therefore the arc PA is at right angles to AC . 11. If the arcs of great circles joining a point P on the surface of a sphere with two other ...
Página 8
... angle corresponding to the spherical triangle . Thus , in the figure of the preceding Article , the arc AB forms one ... right angle , we may say that π 2 ' C = 90 ° , or that C = , according as we adopt for the unit a de- gree or the ...
... angle corresponding to the spherical triangle . Thus , in the figure of the preceding Article , the arc AB forms one ... right angle , we may say that π 2 ' C = 90 ° , or that C = , according as we adopt for the unit a de- gree or the ...
Otras ediciones - Ver todas
Spherical Trigonometry: For the Use of Colleges and Schools Isaac Todhunter Vista de fragmentos - 1949 |
Spherical Trigonometry: For the Use of Colleges and Schools Isaac Todhunter Vista de fragmentos - 1929 |
Términos y frases comunes
A+B+C ambiguity angular points approximately bisecting Cambridge centre circular measure cloth cos b cos cos² cos³ cosine Crown 8vo deduce denote drawn equal angles equilateral example expressed Fcap formulæ formulæ of Art greater Hence hypothenuse inscribed Legendre's Theorem less Let ABC lune meet middle point Napier's analogies Napier's Rules obtained octahedron opposite angle opposite sides parallelopiped perpendicular plane angles plane triangle Plane Trigonometry polar triangle pole polygon preceding article primitive triangle prove quadrant R₁ r₂ radius regular polyhedron respectively right angle right-angled triangles Second Edition shew shewn sides and angles Similarly sin b cos sin b sin sin² sin³ sine solid angle sphere spherical excess spherical triangle Spherical Trigonometry subtended Suppose surface tangent tetrahedron Treatise triangle ABC Trigono Trinity College values π π
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