 | James Maginness - 1821 - 378 páginas
...formula 14. 18 — i^j 18-4-—— 3— — =18+V=26. Ans. 3 — 1 PROBLEM 15. Given, the ratio, tlie number of terms, and the sum of the series, to find the first term. If the ratio be 3, the number of terms 3, and the sum of the series 26; required, the first... | |
 | Nicolas Pike - 1822 - 562 páginas
...the progression. The rule is merely a contraction of this process. PROBLEM IX. Given the first term, number of terms, and the sum of the series, to find the last term. RULE. Divide twice the sum by (ht)' number of terms ; from the quotient take the .first... | |
 | Benjamin Greenleaf - 1839 - 356 páginas
...the sum of the series 528. What is the common difference ? Ans. 2. PROBLEM vI. Given the first term, number of terms, and the sum of the series, to find the last term. RULE. Divide twice the sum by the number of terms, from the quotient take the first term,... | |
 | Benjamin Greenleaf - 1841 - 334 páginas
...the sum of the series 538. What is the common difference ? Ans. 2. PROBLEM vL Given the first term, number of terms, and the sum of the series, to find the last term. RULE. Divide twice the sum by the number of terms, from the quotient take thefirst term,... | |
 | 1843 - 142 páginas
...travelled, and the distance of the cities ? PROBLEM III. Given the common difference, number of terms, and sum of the series, to find the rest. RULE. Divide...will be the greatest and least terms respectively. 9. A person discharged a debt of £210, 12s. in a year, by paying every week 3s. more than he did the... | |
 | Horatio Nelson Robinson - 1861 - 196 páginas
...(numb. ofpaym'ts)=No. of terms; 1.07=ratio; and $3000=sum of the series. That is, we have the ratio, the number of terms, and the sum of the series, to find the first term. $3000 x (1.07— 1=).0 $521.674 (1st installment) + $210 (int. on $3000 for 1 yr.) =$731.674,... | |
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Given the first term, number of terms, and the sum of the series, to find the last term. 