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" Multiply the number of terms, less 1, by the common difference, and to the product add the first term, the sum is the last term. "
The Teachers' Assistant, Or, A System of Practical Arithmetic: Wherein the ... - Página 169
1817 - 198 páginas
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The American Tutor's Assistant Revised, Or, A Compendious System of ...

Zachariah Jess - 1810 - 222 páginas
...10=14; and 6 + 8=14; or 3, 6, 9, 12, 15; where 3+15=18; also 6+12=18; and 9+9=18. CASE 1. The first term, common difference, and number of terms given,...find the last term, and sum of all the terms ; RULE. First, Multiply the number of terms, less .', by the common difference, and to „that produit add...
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The Teachers Assistant. Or, A System of Practical Arithmetic: Wherein the ...

1811 - 210 páginas
...middle term ; as An the former of the foregoing series 6x2=2 + 10, and =t 4 + 8. CASE 1. The first term, common difference, and number of terms given...common difference, and ,to the product add the first teim, the sum is the last term. 2. Multiply the sum of the two extremes by the number of terms, and...
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The American Tutor's Assistant Revised, Or, A Compendious System of ...

Zachariah Jess - 1813 - 228 páginas
...3+15=18 ; also ß+ 12^18; ana 9+9=18. CASE I*' The first term, common difference, and number of terra* given, to find the last term, and sum of all the terms ; RULE. First, Multiply the number of terms, less r, by tfee common différence, and to that product add the...
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The Scholar's Arithmetic: Designed for the Use of Schools in the United States

Jacob Willetts - 1822 - 200 páginas
...sum of all the terms ; Any three of which being given, the other two may be found, CASK 1 . The First term, common difference, and number of terms given to find the last term, and the sum of all the terms. RFLE. First, Multiply the number of terms, less 1, by the common .difference,...
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The American Tutor's Assistant Revised: Or, A Compendious System of ...

Zachariah Jess - 1824 - 228 páginas
...difference, and number of term's given, to find the last term, a»d sum of all the terms; RULE. First, Multiply the number of terms, less 1, by the common difference, and to that product add the first term, the sum is the last term. Secondly, Multiply the sum of the two extremes...
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Elements of Arithmetic

Etienne Bézout - 1824 - 238 páginas
...rules in the two following cases. CASE I. When the first term, common ratio, and number of terms are given, to find the last term, and sum of all the terms, the operation is as follows. Multiply the number of terms, less 1 , by the common difference ; to the...
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The New Federal Calculator, Or, Scholar's Assistant: Containing the Most ...

Thomas Tucker Smiley - 1825 - 224 páginas
...Progression. By what rule do you work when the first term, common difference, and number of terms are given to find, the last term, and sum of all the terms ? By \vhat rule do you work when the first and last terms are given to find the common difference ?...
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The American Tutor's Assistant, Improved: Or, A Compendious System of ...

Zachariah Jess - 1827 - 226 páginas
...4+10=14; and 6+8 = 14; or, 3, 6, 9, 12, 15, where 3+ 10= 18; abo 6+ 12=18; and 9+ 9=18. CASE !.. The first term, common difference, and number of terms given,...find the last term, and sum of all the terms. RULE. First, Multiply the number of terms, less one, by the common difference, and to that product add the...
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The Common School Manual: A Regular and Connected Course of Elementary ...

Montgomery Robert Bartlett - 1828 - 426 páginas
...first term, the common difference, and the number of terms are given, to find the last term, and the sum of all the terms;— RULE. 1. Multiply the number of terms, less by, 1, by the common difference, and, to the product, add the first term, the sum will be the last...
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The Juvenile Arithmetick, and Scholar's Guide: Wherein Theory and Practice ...

Martin Ruter - 1828 - 180 páginas
...together make the same amount. CASE I. The first term, common difference, and number of terms, being given, to find the last term and sum of all the terms. RULE. Multiply the common difference by one less than the number of terms, and to the product add the first...
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