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" Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. "
A System of Arithmetic: Reprinted from the Mathematical Text-book - Página 112
por Samuel Webber - 1812 - 248 páginas
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Mathematics: Compiled from the Best Authors and Intended to be the ..., Volumen1

1801 - 446 páginas
...of the same kind with the answer required. 2. Bring 3. Multiply the second and third terms together, divide the product by the first, and the quotient will be the answer. NOTE 1. 2. Bring the first and third numbers into the same denomination, and the second into the lowest...
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A Treatise on Plane and Spherical Trigonometry: With Their Most Useful ...

John Bonnycastle - 1806 - 464 páginas
...method, having stated the proportion, according to the proper rule, multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term required, for the natural numbers. Or, in working by logarithms, add the logarithms of...
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The Tutor's Guide: Being a Complete System of Arithmetic; with Various ...

Charles Vyse - 1806 - 342 páginas
...mentioned. 3. Multiply the second and third Terms together, and divide that Product by the first. ' The Quotient will be the Answer to the Question, in the same Denomination or Name you left your second Term in. 4. If there happens to be a Remainder after the Division, reduce...
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The Scholar's Arithmetic; Or, Federal Accountant ...: The Whole in a Form ...

Daniel Adams - 1807 - 248 páginas
...first, and the remaining one for the second term. 2. Multiply the second and third terms together, divide the product by the first, and the quotient will be the answer. EXAMPLES. 1. If 30 horses plough 12 acres, how many will 40 plough in the same time? OPERATION^ HH...
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A New System of Mercantile Arithmetic: Adapted to the Commerce of the United ...

Michael Walsh - 1807 - 290 páginas
...the first and third numbers into the same, and the second into the lowest denomination mentioned. 2. Multiply the' second and third numbers together, and divide the product by Ae first, and the quotient (if there be no remainder) i;s the answer, or fourth number required. If,...
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The Federal Arithmetic; Or, A Compendium of the Most Useful Rules of that ...

James Noyes - 1808 - 168 páginas
...same name with the answer required, the second term. 2. Multiply the second and third terms together, divide the product by the first, and the quotient will be the answer. Note \ , Whefi the second term consists of more than one denomination, reduce it to the lowest mentioned...
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A New and Complete System of Arithmetick: Composed for the Use of the ...

Nicolas Pike - 1808 - 470 páginas
...then proceed as in the common method, by multiplying the second and third terms together, and dividing the product by the first, and the quotient will be the answer, in the same name as the third term was reduced into. 54. If 15 yards of cloth cost 55. If 12 men can...
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A System of Practical Arithmetic: Applicable to the Present State of Trade ...

Jeremiah Joyce - 1812 - 274 páginas
...thefirst and third numbers into the same denomination, and the second into the lowest denomination mentioned. 3. Multiply the second and third numbers...by the first, and the quotient will be the answer, * in the same denomination as that in which the second number wus left. * If there be a remainder after...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged : Being a Plain and ...

Nathan Daboll - 1813 - 244 páginas
...in it. 3. Multiply the second and third terms together, and divide their product by the first term; and the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought into any other denomination required. Tlie method of proof is by inverting...
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Daboll's Schoolmaster's Assistant: Improved and Enlarged, Being a Plain ...

Nathan Daboll - 1815 - 250 páginas
...in it. 3. Multiply the second and third terms together, and divide their product by the first term ; the quotient will be the answer to the question, in the same denomination you left the second term in, which may be brought inta any other denomination required. . Thn method of proof is by inverting...
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