 | Robert Gibson - 1806 - 486 páginas
...Calculation. 1. AB : AC + BC : : AC— BC : AD— DB. 2.5 4.3 .3 .516 By cor. 2. theo. 14. sect. 1. The square root of the difference of the squares of the hypothenuse AC, and given leg AD, wtll give DC. ie 5.29—2.274064=3.015936. Its square root is 1.736=CD. • Then... | |
 | Robert Gibson - 1808 - 482 páginas
...AC+BC : : AC— BC : AD— DB. 2.5 4.3 .3 .516. 1>25+.258=1.50S=AD. By cftr. 2. theo. 14. sett. 1. The square root of the difference of the squares of the hypothenuse AC, and given leg AD, will give DC. i. e* 5.29—2.274064=3.015936. Its square root is 1.736=CD. Then... | |
 | Robert Gibson - 1811 - 580 páginas
...of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the other ; the square root of the difference of the squares of the hypothenuse and given side, will be the required side. THEO. XV . PL. \.fig. 33. />; all circle* the chord of 60 dt'grtct... | |
 | Robert Gibson - 1814 - 558 páginas
...required. By Calculation. 1. AB : AC+BC- - AC—BC: AD—DB. 2.5 4.3 .3 .516. By cor. 2. theo. 14. geom. The square root of the difference of the- squares of the hypothenuse AC, and given leg AD, will give DC. That is, 5.29—2.274064=3.015936. « Its square root is 1.736=... | |
 | John Bonnycastle - 1818 - 488 páginas
...square root of the sum of the squares of the other two sides ; and either of the sides is equal to the square root of the difference of the squares of the hypothenuse and the other side. Note, also, that if the half difference of any two quantities be added to their half... | |
 | Robert Gibson - 1821 - 594 páginas
...squares of the base andperpendiculariwillbe the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the other ; the square root of the difference of the squares ofthe hypothenuse and given side, will be the required side. * For different demonstrations of this... | |
 | L. Murray - 1821 - 620 páginas
...scaling-ladder. 25 (0) Case 2. If the length of the base, or breadth of the ditch, were required ; then the square root of the difference of" the squares of the hypothenuse and perpendicular is the length of the base, or breadth of the ditch or moat. See the work. 2500 the square... | |
 | James Hale - 1829 - 124 páginas
...Squares, of the Base and Perpendicular, will be the Hypothenuse. — Having the Hypothenuse, and one Side, given to find the other ; The Square Root, of the difference of the Squares, of the Hypothenuse and the given Side, will be the required Side. REMARK IV. Triangles, having the same height, and standing... | |
 | Michael Walsh - 1831 - 348 páginas
...top of the wall. Ans. 39,05 feet. The hypolhenuse and perpendicular given, to find the base. RULE. The square root of the difference of the squares of the hypothenuse and perpendicular is the length of the base. The base and hypothenuse given, to find the perpendicular.... | |
 | Francis Walkingame - 1832 - 224 páginas
...perpendicular is the length of the base. The Bate and Hypothenate given tollnd the Perpendicular. KUI.E. The square root of the difference of the squares of the hypothenuse and base is the height of the perpendicular. NB The two last Quettiont may be varied for Examples to At... | |
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The hypothenuse of a right-angled triangle may be found by having the other two sides ; thus, the square root of the sum of the squares of the base and perpendicular, will be the hypothenuse. Cor. 2. Having the hypothenuse and one side given to find the... 
