Elements of Plane and Spherical Trigonometry: With Their Applications to Heights and Distances Projections of the Sphere, Dialling, Astronomy, the Solution of Equations, and Geodesic OperationsBaldwin, Cradock, and Joy, 1816 - 244 páginas |
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Página xii
... drawn from C to the point of contact A , in the first figure . 29 , line 8 , for answer read answers 37 , line 2 , for and is read it is a a 41 , line 3 , for read .. с C 156 , Ex . 1. Add , In the Connaissance des Tems , pour l'an 1817 ...
... drawn from C to the point of contact A , in the first figure . 29 , line 8 , for answer read answers 37 , line 2 , for and is read it is a a 41 , line 3 , for read .. с C 156 , Ex . 1. Add , In the Connaissance des Tems , pour l'an 1817 ...
Página 3
... draw DE , another diameter , to meet the circle in D , E. F D E B Then , Euc . vi . 33 , ang . ACB : right ang . ACD :: arc AB : arc AD , and , Euc . v . 4 , cor . quadrupling the consequents , we have , angle ACB : 4 right angles ...
... draw DE , another diameter , to meet the circle in D , E. F D E B Then , Euc . vi . 33 , ang . ACB : right ang . ACD :: arc AB : arc AD , and , Euc . v . 4 , cor . quadrupling the consequents , we have , angle ACB : 4 right angles ...
Página 5
... drawn T and limited by CT : let GB and EM be drawn parallel to AA ' , B ' E ' the latter being limited by CT or CT produced . Then BE is the complement of BA , and angle BCE the comple- ment of angle BCA ; BEA ' is the supplement of BA ...
... drawn T and limited by CT : let GB and EM be drawn parallel to AA ' , B ' E ' the latter being limited by CT or CT produced . Then BE is the complement of BA , and angle BCE the comple- ment of angle BCA ; BEA ' is the supplement of BA ...
Página 14
... drawn parallel to BS , or perpendicular to the radius CB . B H R A R T Then , because of the similar triangles TAC , THR , we shall have , TC : CA :: TR : RH , whence TC . RH = CA. TR , TC : TA :: TR : TH , whence TC . TH = TA . TR ...
... drawn parallel to BS , or perpendicular to the radius CB . B H R A R T Then , because of the similar triangles TAC , THR , we shall have , TC : CA :: TR : RH , whence TC . RH = CA. TR , TC : TA :: TR : TH , whence TC . TH = TA . TR ...
Página 15
... drawn parallel to the diameter A AA ' . Draw ID , IE , from the cen- tre 1 with the radius CA of the as- sumed circle , describe an arc dbe , and through b draw Loм parallel - D B N G K L M - BG BCD to DE . Then , it is evident that NE ...
... drawn parallel to the diameter A AA ' . Draw ID , IE , from the cen- tre 1 with the radius CA of the as- sumed circle , describe an arc dbe , and through b draw Loм parallel - D B N G K L M - BG BCD to DE . Then , it is evident that NE ...
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Términos y frases comunes
altitude angled spherical triangle azimuth base becomes bisect centre chap chord circle circle of latitude computation consequently cos² cosec cosine cotangent declination deduced determine dial diameter difference distance draw earth ecliptic equa equal equation Example find the rest formulæ given side h cos h half Hence horizon hour angle hypoth hypothenuse intersecting latitude logarithmic longitude measured meridian obliq oblique opposite angle parallel perpendicular plane angles plane triangle pole problem prop quadrant radius right angled spherical right angled triangle right ascension right line sec² secant sin A sin sin² sine solid angle sphere spherical excess spherical trigonometry star substyle sun's supposed surface tan² tangent theorem three angles three sides tion triangle ABC values versed sine versin vertical angle whence zenith