 | 1801 - 658 páginas
...street. • t Ans. 76- 1 2333 35 feet. PROBLEM IV. 7o f:nd tlie area of a trapezoid. • RULE.* Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. • EXAMPLES. * DEMONSTRATION. or (because B»=DE) =-, .-. A... | |
 | Thomas Keith - 1817 - 306 páginas
...trapezium 85342'2885 yards, or 17•6327 acres; or 17 acres. <• 2 roods 21 perches. PROBLEM VIII. • To find the Area of a Trapezoid. RULE *. Multiply...sides by the perpendicular distance between them, and the product will be the area. Example 1. Let AB c D JE. be a trapezoid, the side '-. A )•. —... | |
 | Anthony Nesbit, W. Little - 1822 - 916 páginas
...Ant. 97.3383 bushels. PROBLEM VII. To Jind the area of a trapezoid. RULE. • By the Pen. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area in square inches. Divide this area by 2 82, 231, and 2150.42,... | |
 | John Nicholson - 1825 - 822 páginas
...square 63 I 189 of AB has been subtracted. 3 I 189 Prob. 4. To find the Area of aTrapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12,... | |
 | Zadock Thompson - 1826 - 176 páginas
...rods ; what is the area ? Ans. 54.299 rods. I Problem III. Tojind the area of a trapezoid. :BuLE.— Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Examples. 1. One of the two parallel sides of a trapezoid is 7.5... | |
 | James Hale - 1829 - 124 páginas
...(See Def. 32, 33, and 35, Part. 1, Sec. 1.) PROBLEM VI. To find the Area of a Trapezoid. (See Def.M.) Multiply half the sum of the two Parallel Sides by the Perpendicular Height, the Product is the Area. PROBLEM VII. To find the Area of a Trapezium. (See Def. 36 and S7.)... | |
 | John Nicholson (Civil engineer) - 1830 - 240 páginas
...square 63 I 189 of AB has been subtracted. 3 I 189 Prob. 4. To find the Area of aTrapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12,... | |
 | Ira Wanzer - 1831 - 408 páginas
...many acres are contained in a triangle whose sides are 30, 40, and 50 rods? Ans. 3f A. PROBLEM V, — To find the area of a Trapezoid. RULE. — Multiply...sides by the perpendicular distance between them, and the pr«' duct will be the area. Ex. How many square feet are contained in a board which is 12... | |
 | Zadock Thompson - 1832 - 186 páginas
...16, 11 and 10 rods ; what is the area ? Ans. 54.299 rods. 307. To find the area of a trapezoid. (65) RULE. — Multiply half the sum of the two parallel...sides by the perpendicular distance between them, and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and... | |
 | Zadock Thompson - 1832 - 186 páginas
...16, 11 and 10 rods ; what is the area ? Ans. 54.299 rods. 307. To find (he. area of a trapezoid. (65) RULE. — Multiply half the sum of the two parallel...sides by the perpendicular distance between them, and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and... | |
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To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be the area. 
