 | Benjamin Franklin Foster - 1837 - 224 páginas
...side, as before. Second. Multiply the smallest sum by the number of days between the dates, thus found, and divide the product by the balance of the account; the quotient is the number of days to be carried back or forward, as the case may require, ftj" If the balance be... | |
 | Benjamin Franklin Foster - 1837 - 262 páginas
...side, as before. Second. Multiply the smallest sum by the number of days between the dates, thus found, and divide the product by the balance of the account ; the quotient is the number of days to be carried back or forward, as the case may require. QJ0 If the balance be... | |
 | Benjamin Franklin Foster - 1837 - 156 páginas
...side, as before. Second. Multiply the smallest sum by the number of days between the dates, thus found, and divide the product by the balance of the account; the quotient is the number of days to be carried back or forward, as the case may require. (j^r3 If the balance... | |
 | Benjamin Franklin Foster - 1843 - 142 páginas
...side, as before. Secoud: Multiply the smallest sum by the number of days between the dates, thus found, and divide the product by the balance of the account ; the quotient is the number of days to be carried back or forward, as the case may require. QJ" If the balance be... | |
 | George Nixon Comer - 1846 - 122 páginas
...equation. Multiply the number of days between the averaged dates by the smallest amount, and divide this product by the balance of the account, the quotient will be the time required for calculation. If the largest amount falls due first, the time is counted back from... | |
 | George Nixon Comer - 1847 - 124 páginas
...equation. Multiply the number of days between the averaged dates by the smallest amount, and divide this product by the balance of the account, the quotient will be the time required for calculation. If the largest amount falls due first, the time is counted back from... | |
 | Rufus Putnam - 1849 - 402 páginas
...of the Dr. and Cr. sides; then multiply the sum first due by the number of days between the dates, and divide the product by the balance of the account ; the quotient will be the equated time in days from the LATEST DATE ; to be reckoned BACKWARD, if the sum last due is the smaller... | |
 | Christopher Columbus Marsh - 1851 - 236 páginas
...days that intervene between the day on which it is due and the day on which the larger side is due, and divide the product by the balance of the account; the quotient will be the number of days that the balance will be due after or before the date of the larger side. 89 days from June 5 to Sept.... | |
 | Christopher Columbus Marsh - 1853 - 156 páginas
...smaller side by the number of days that intervene between its date and the date of 'the larger side, and divide the product by the balance of the account ; the quotient will be the number of days before or after the date of the larger side. Calculation— $557 7 days that intervene. The Balance...... | |
 | Horace Mann - 1855 - 272 páginas
...account. 2d. Multiply the least side of the account by the time between the dates found for each side, and divide the product by the balance of the account. The quotient will be the time between the date found for the larger side of the account, and the equated time for the settlement... | |
| |
Multiply the amount of the smaller side by the number of days between the two average dates, and divide the product by the balance of the account. The quotient will be the time... 
