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" To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance ; the Product will be the Area. "
The Carpet-dealer's Guide: A Manual of Practical Information on the Art of ... - Página 48
por John H. Macke - 1891 - 228 páginas
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A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - 1804 - 168 páginas
...Angle 28° 5'. 0.47076 105X85=8925, and 8925X0.47076=4201 the double Area of the Triangle. PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the Sum of the two parallel Sides by half the perpendicular...
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A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - 1808 - 168 páginas
...28* 5'. 0.47076 105x85=8925, and 8925x0.47076=4201 the double Area of the Triangle. • PROBLEM X. To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular...
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A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - 1813 - 168 páginas
...and 8925X0.47076=4201 the double Area of the Triangle. PROBLEM X. To find the Area of a Trapezovl. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular...
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The complete measurer: or, The whole art of measuring, containing the ...

Thomas Keith - 1817
...trapezium 85342'2885 yards, or 17•6327 acres; or 17 acres. <• 2 roods 21 perches. PROBLEM VIII. • To find the Area of a Trapezoid. RULE *. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. Example 1. Let AB c D JE. be...
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A System of Geometry and Trigonometry: Together with a Treatise on Surveying ...

Abel Flint - 1825 - 241 páginas
...and 8925 X 0.47076=4201 tbe double Area of the Triangle. PROBLEM X. To find the Jbeaof a TrapezoiA. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular...
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A New and Easy Introduction to the Mathematics: Containing. A system of ...

Ira Wanzer - 1831 - 396 páginas
...many acres are contained in a triangle whose sides are 30, 40, and 50 rods? Ans. 3f A. PROBLEM V, — To find the area of a Trapezoid. RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the pr«' duct will be the area. Ex. How many square feet...
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The Youth's Assistant in Theoretic and Practical Arithmetic: Designed for ...

Zadock Thompson - 1832 - 168 páginas
...16, 11 and 10 rods ; what is the area ? Ans. 54.299 rods. 307. To find the area of a trapezoid. (65) RULE. — Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. 1. One of the two parallel sides...
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The Youth's Assistant in Theorhetic [sic] and Practical Arithmetic: Designed ...

Zadock Thompson - 1832 - 168 páginas
...16, 11 and 10 rods ; what is the area ? Ans. 54.299 rods. 307. To find the area of a trapezoid. (65) RULE.— Multiply half the sum of the two parallel sides by the perpendicular distance hetween them, and the product will he the area. , 1. One of the two parallel...
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A treatise on practical geometry, mensuration, conic sections, gauging, and ...

Ireland commissioners of nat. educ - 1834
...as follows, viz. AB 25, AD 34, D С 35, and B С 16 ; required its area ? Ans. 700-99. PROBLEM XIII. To find the area of a Trapezoid RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will give the area.* 1. Let A BCD be a trapezoid,...
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A System of Geometry and Trigonometry: With a Treatise on Surveying; in ...

Abel Flint - 1835 - 334 páginas
...of the angle 28° 5' 0.47076. 105x85=8925, and 8925x0.47076=4201 the double area. pf the triangle. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, or the sum of the two parallel sides by half the perpendicular...
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