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Libros Libros 1 - 10 de 142 sobre To prove that the exterior angle of a triangle is equal to the sum of the two interior...
" To prove that the exterior angle of a triangle is equal to the sum of the two interior opposite angles (see fig. "
A complete system of mensuration, with additions by J. Trotter - Página 144
por Alexander Ingram - 1851
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A Course of Mathematics ...: Composed for the Use of the Royal Military ...

Charles Hutton - 1811
...c, the measure of ACE, supposing there to be • known АРБ = p, UPC = p, CP =: d, BC = L, AC = R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles (th. 16 Geom.), we have, with respect to the triangle IAP, AIB = p -f- IAP ; and with...
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A Course of Mathematics: For the Use of Academies as Well as ..., Volumen2

Charles Hutton - 1812
...to find c, the measure of ACB, supposing there to be known APB = r, BPC =fi, CP = d, BC = L, AC = R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles (th. 1 6 Geom.), we have, •with respect to the triangle IAP, AIB = P+IAP; and with...
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A Treatise on Surveying, Containing the Theory and Practice: To which is ...

John Gummere - 1814 - 346 páginas
...took the angle of elevation BAG = 26° 30'. Required the height of the tree. Calculation. 1. Because the exterior angle of a triangle is equal to the sum of the two interior and opposite ones, the angle BDC = DAC + ACD ; therefore ACD - BDC — DAG = 25° : now in the triangle ADC we have...
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Elements of Plane and Spherical Trigonometry: With Their Applications to ...

Olinthus Gregory - 1816 - 244 páginas
...staof the centre of 'r the sutnmit of ;Ie APB : it is re* the measure of here to be known p, ce = d,BQ Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, we have, with respect to the triangle IAP, AIB = P + IAP; and with regard to the triangle...
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An Elementary Treatise on the Application of Trigonometry: To Orthographic ...

John Farrar - 1822 - 153 páginas
...another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 45'. Now, sinre the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have that is 4l° — 23° 45' =17° 15'. Hence in the triangle BAC....
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An Elementary Treatise on the Application of Trigonomentry to Orthographic ...

John Farrar - 1833 - 155 páginas
...measure another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 45'. Now, since the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have ACD — A&b = BAC. that is 41° — 23° 45' = 17° 15'. Hence...
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An Elementary Treatise on the Application of Trigonomentry to Orthographic ...

John Farrar - 1833 - 155 páginas
...measure another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 45'. Now, since the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have ACD — ABC = EAC. that is 41° — 23° 45' = 17° 15'. Hence...
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The Schoolmaster: Essays on Practical Education, Selected from the ..., Volumen1

1836
...example, suppose it known that the angles at the base of an isosceles triangle are equal, and also that the exterior angle of a triangle is equal to the sum of the interior and opposite angles. Suppose it also indisputable, that if A and B be respectively double...
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The schoolmaster: essays on practical education, selected from the works of ...

Schoolmaster - 1836
...example, suppose it known that the angles at the base ofan isosceles triangle are equal, and also that the exterior angle of a triangle is equal to the sum of the interior and opposite angles. Suppose it also indisputable, that if A and B he respectively double...
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A system of practical mathematics; being no.xvi. of a new series of school-books

1845
...required to find C, the measure of ACB, supposing there to be known APB=P, BPC= p, CP=d, BC=L, AC=R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, (Geo. prop. ] 9), we have, with respect to the triangle IAP, ZAIB=ZP+UAP ; and with...
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