## Elementary Algebra: For the Use of Schools |

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added addition algebraic amount answer arithmetical becomes bought called cents coefficient common consists contain cost denominator difference distance divided dividend division divisor dollars double employed equal equation evident example exponent expression extracting factors feet figure Find the values formula four fourth fraction gain gallons given gives greater half hand increased interest kind known length less letter logarithm manner means miles monomials multiplied negative obtain operations paid perform persons piece polynomials positive pound preceding principal progression proportion proposed purchase quantity question quotient ratio received Reduce remainder represent respectively result rule seen share shillings sides solution solved square root subtracted Suppose taken tens third tion trade traveled twice units unknown quantity whence whole worth yards

### Pasajes populares

Página 188 - A labourer dug two trenches, one of which was 6 yards longer than the other, for 17/. 16s., and the digging of each of them cost as many shillings per yard as there were yards in its length. What was the length of each ? Ans. 10, and 16 yards.

Página 161 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.

Página 119 - In a series of equal ratios, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent.

Página 93 - What fraction is that, to the numerator of which if 1 be added, the value...

Página 139 - Multiply £ the sum of the extremes by the number of terms, and the product will be the answer 10.

Página 61 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.

Página 57 - Divide the coefficient of the dividend by the coefficient of the divisor.

Página 179 - Divide the number 14 into two such parts, that the quotient of the greater divided by the less, shall be to the quotient of the less divided by the greater as 16 to 9.

Página 13 - It is required to divide the number 99 into five such parts, that the first may exceed the second by 3, be less than the third by 10, greater than the fourth by 9, and less than the fifth by 16. Let x= the first part.

Página 192 - This result indicates, that there is some absurdity in the conditions of the question proposed, since in order to obtain the value of x, we must extract the root of a negative quantity, which is impossible. In order to see in what this absurdity consists, let us examine into what two parts a given number should be divided, in order that the product of these parts may be the greatest possible. Let us represent the given number by p, the product of the two parts by q, and the difference of the two...