 | Jeremiah Day - 1820 - 352 páginas
...did each pay ? Ans. 317, 951, 1268, 2219. Prob. 32. It is required to divide the number 99 into five" such parts, that the .first may exceed the second...fifth by 16. .' Let x— the first part. Then x— 3= the second, a; — 9= the fourth, x+ 10= the third, x+ 16= the fifth. Therefore x + x-3+x+10+x-9+x+... | |
 | Miles Bland - 1821 - 898 páginas
...received 40, 30, 26, 15, 12, 7 pence respectively. 14. It is required to divide the number 99 into five such parts, that the first may exceed the second by 3 ; be less than the third by ю ; greater than the fourth by 9 ; and less than the fifth by 16. Let x = the first part, .". x —... | |
 | Miles Bland - 1824 - 404 páginas
...received 40, 30, 26, 15, 12, 7 pence respectively. 14. It is required to divide the number 99 into five such parts, that the first may exceed the second by...less than the fifth by 16. Let x = the first part, .'. x— 3 = second, т +10= third, x— 9= fourth, x + 16 = fifth. or 5т+14 = 99, .'. by transposition,... | |
 | James Ryan, Robert Adrain - 1824 - 542 páginas
...21, 30, 42, and 60 shillings respectively. Prob. 4D. It is required to divide the number 99 into five such parts, that the first may exceed the second by...than the fourth by 9 ; and less than the fifth by 16. Ans. 17, 14,27, 8, and 33. Prob. 50. Two persons began to play with equal sums of money : the first... | |
 | James Ryan - 1824 - 550 páginas
...21, 30, 42, and 60 shillings respectively. Prob. 49. It is required to divide the number 99 into fire such parts, that the first may exceed the second by...than the fourth by 9; and less than the fifth by 16. Ans. 17, 14, 27, 8, and 33. Prob. 50. Two persons began to play with equal sums of money : the first... | |
 | James Ryan - 1826 - 430 páginas
...21, 30, 42, and 60 shillings respectively. Prob. 49. It is required to divide the number 99 into five such parts, that the first may exceed the second by 3 ; be lest than the third by 10; greater than the fourth by 9 ; and less than the tilth by 16. Ans. 17, 14,... | |
 | Jeremiah Day - 1827 - 352 páginas
...What did each pay? Ans. 317,951,1268,2219. Prob. 32. It is required to divide the number 99 into five such parts, that the first may exceed the second by...fifth by 16. Let x= the first part. Then x — 3= the seco"nd, x— 9= the fourth, z+ 10= the third, x + 16= the fifth. Therefore x+x — 3+x+10+x-9+x+... | |
 | Jeremiah Day - 1831 - 358 páginas
...did each pay 1 Ans. 317, 951, 126& 2219. Prob. 32. It is required to divide the number' Tfe'into five such parts, that the first may exceed the second by...than the fourth by 9, and less than the fifth by 16. Then x - 3 = the second, x - 9 = the fourth, Let x= the first part. . a;4-10= the third, a;+l6= the... | |
 | Jeremiah Day - 1832 - 360 páginas
...did each pay ? Ans. 317, 951, 1268, 2219. Prob. 32. It is required to divide the number 99 into five such parts, that the first may exceed the second by...the fourth by 9, and less than the fifth by 16. Let a;= the first part. Then x - 3= the second, x - 9= the fourth, a;+ 10= the third, a;-f- 16= the fifth.... | |
 | Silas Totten - 1836 - 320 páginas
...gave 6, 12, 18, and 24 pence to them respectively. 4. It is required to divide the number 99 into five such parts, that the first may exceed the second by...fifth by 16, Let x = the first part ; then x — 3 = the second, x + 10 = the third, x — 9 — -the fourth, ar+16 = the fifth, The sum of all the parts... | |
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It is required to divide the number 99 into five such parts, that the first may exceed the second by 3, be less than the third by 10, greater than the fourth by 9, and less than the fifth by 16. Let x= the first part. 
