 | John Playfair - 1806 - 320 páginas
...straight line which joins the points of section will bt parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC ; BD is to DA, as CE to EA. Book VI. Join BE, CD ; then the triangle BDE is equal to the triangle CDEa.... | |
 | Robert Simson - 1806 - 546 páginas
...straight line which joins the points of section shall be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the trian- • gle ABC : BD is to DA, as CE to EA. Join BE, CD ; then the triangle BDE is equal to the... | |
 | Euclid - 1810 - 554 páginas
...straight line which joins the points of section shall be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC: BD is to DA, as CF. to E A. Ioin BE, CD; then the triangle BDE is equal to the triangle CD E*, because... | |
 | Euclides - 1816 - 588 páginas
...straight line which joins the points of section shall be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC : BD is to DA, as CE to EA. - Join BE, CD; then the triangle BDE is equal to the triangle CDEa, because... | |
 | John Playfair - 1819 - 354 páginas
...straight like which joins the points of section will be parallel to the remaining side of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC : BD is to DA, as CE to EA. Join BE, CD ; then the triangle BDE is equal to the triangle CDE (37. 1.),... | |
 | Anthony Nesbit - 1824 - 476 páginas
...then the angle ABC in that semicircle, is a right angle. (Euc. III. 31. Simp. III. 13. Em. vI. 14.; B THEOREM X. Let DE be drawn parallel to BC, one of...DA, as CE to EA. (Euc. vI. 2. Simp. IV. 12. Em. II. 12J DB THEOREM XI. In the preceding figure, DE being parallel to BC, the triangles ABC, ADE are equi-angular... | |
 | Peter Nicholson - 1825 - 1046 páginas
...ânes tvhich joins ¡he points of section shall be parallel to the remaining tide of the triangle. Let DE be drawn parallel to BC, one of the sides of the triangle ABC : BD is to DA, as CE to EA. Join BE, CD; then the triangle RUH U equal to the triangle CDE, (87.) because... | |
 | Robert Simson - 1827 - 546 páginas
...joins the points of section shall be parallel to the remaining side of the triangle. a \ •-, " • Let DE be drawn parallel to BC, one of the sides of the triangle ABC : BD shall be to DA, as CE to EA. * 37. 1. Join BE, CD ; then the triangle BDE is equal* to the triangle... | |
 | John Playfair - 1833 - 346 páginas
...line which joins the points of section will be parallel to the remaining side of the triangle. Let BE be drawn parallel to BC, one of the sides of the triangle ABC : BD is to DA as CE to EA. Join BE, CD ; then the triangle BDE is equal to the triangle CDE (37. 1.),... | |
 | Euclid - 1835 - 540 páginas
...line which joins the points of section will be parallel to the remaining side of the triangle. • Let DE be drawn parallel to BC, one of the sides of...the triangle ABC ; then BD is to DA, as CE to EA. Join BE, CD ; then the triangle BDE is equal to the triangle CDE a, because they are on the same base... | |
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... proportionally : and if the sides, or the sides produced, be cut proportionally, the straight line which joins the points of section, shall be parallel to the remaining side of the triangle. 
