 | Em Develey - 1816 - 332 páginas
...ensorte que l'on aurait , comme on le voit sans calcul , et par la simple permutation des lettres : cot a sin c = cot A sin B + cos c cos B , cot a sin b = cot A sin C + cos b cos C , cot b sin a = cot B sin C + cos a cos C , ^ , ™ cot b... | |
 | Robert Woodhouse - 1819 - 300 páginas
...determination of C does not require the previous determination of B, for by the third equation, p. 157, cot. A. sin. C = cot- a . sin. b — cos- C . cos. b, in which A, a, b, C are alone involved. But, this form is not adapted to logarithmic computation ;... | |
 | Louis Puissant - 1819 - 464 páginas
..., , , , . , sin a sin C , trouvée précédemment, pour sin c sa valeur — ^-^ — , on a de suite cot A sin C= cot a sin b — cos C cos b, et par conséquent . cot a sin & . ^ » cot ^4. = — ^-77 -- cot C cos b. sin C Cette formule donne... | |
 | University of Cambridge - 1849 - 560 páginas
...between — and — , when the tangent of the angle is given 1 6. Prove that in any spherical triangle cot a sin c = cot A sin B + cos c cos B. 7. Investigate Napier's rules for solving a right-angled spherical triangle, when one side is taken... | |
 | Dublin city, univ - 1857 - 692 páginas
...points, A, fl, prove that tan %OA . tan JOJ? is constant. 7. In a spherical triangle prove the relation cot A sin C = cot a sin b — cos C cos b. 8. Find an expression for the tangent of the radius of the circumscribing circle of a spherical triangle.... | |
 | John Hymers - 1858 - 292 páginas
...sin (B — A) we get cos C = - ; — -, - "• . sin $ Also, a may be independently determined from the formula cot a sin c = cot A sin B + cos c cos B ( D , D = cos c I cos B + sin 5 cos c I ' which, upon introducing the same subsidiary angle <£, becomes... | |
 | Oskar Xaver Schlömilch - 1859 - 566 páginas
....#) cos (180° — c) oder — cot A sin B = — cot a sin c + cos B cos c, und bei anderer Anordnung cot a sin c = cot A sin B + cos c cos B, 5) cot c sinb = cot C sin A -\-cosb cos A, cotb sin a — cot B sin C + cosa cos C. Der Sache nach... | |
 | William Thomas Read - 1862 - 144 páginas
...And dividing by sin A sin C, cot a sin b = cot A sin C + cos b . cos C ; which may be written also, cot A sin C = cot a sin b — cos C cos b. Napier's Rules for the Solution of Right-angled Spherical Triangles. Let ABC be a spherical triangle;... | |
 | Benjamin Greenleaf - 1863 - 502 páginas
...cot a sin ft = cot A sin (7 -[- cos ft cos (7. 152. By interchanging the letters in (156), we obtain cot a sin c = cot A sin B -\- cos c cos B, cot ft sin a = cot J5 sin C -\- cos a cos (7, cot ft sin c = cot .2? sin A -|- cos c cos A 9 cot c... | |
 | Dublin city, univ - 1871 - 366 páginas
...on a right line ; find the locus of the third vertex. 3. Prove the formula in spherical trigonometry cot A sin C = cot a sin b — cos C cos b. 4. Prove that . cos^e 5. A bar of iron of uniform thickness, 10 feet long, is supported at its extremities... | |
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B, cot a sin c = cot A sin B + cos c cos B. 
