| Peter Nicholson - 1809 - 426 páginas
...ii. iii. PROBLEM II. To find the solidity of a sphere or globe. Multiply the cube of the diameter AB by 5236, and the product is the solidity. EXAMPLE. What is the solidity of a globe, whose diameter is 3 feet ? 3 X 3 X 3 = 27 And '5'236 27 3S652 10472 IV 1372 the solidity of... | |
| Nicolas Pike - 1822 - 536 páginas
...solid body, in the middle of which is a point, from which all lines drawn to the surface are equal. RULE. Multiply the cube of the diameter by -5236, and the product will be the solid content. Or, multiply the circumference by the diameter, which will give the superficial... | |
| Peter Nicholson - 1825 - 1046 páginas
...1728)4240(2 solid ft. and 784 solid in. the Ans. 345Ü Prob. 20. To find (he solidity of a sphere or globe. Multiply the cube of the diameter by -5236, and the product is it» solidity. Ex. What is the solidity of a globe, whose diameter is 3 feet ? 3X3X3 = 27 And -5231)... | |
| Zadock Thompson - 1826 - 176 páginas
...feet, and the sides of its base being 5, 6, and 7 feet ? Ans. 71.035+ Problem VI. Tofind the tolidily of a sphere.* RULE. — Multiply the cube of the diameter by .5236, or multiply ihe square of the diameter by £ the circumference. Examples. 1. What is the content of... | |
| John Bonnycastle - 1829 - 256 páginas
...was cut, 25 inches ? Ans. 314.16 inches. PROBLEM XIII, .. To find the solidity of a sphere or globe.. RULE.* "... Multiply the cube of the diameter by .5236, and the product will be the solidity. * . MENSURATION ' EXAMPLES. I/What is the solidity of the sphere AEBC, whose... | |
| James L. Connolly (mathematician.) - 1829 - 266 páginas
...feet diameter. Ans. The diameter of a balloon given to find what weight it is • capable of raisin*. RULE. Multiply the cube of the diameter by ,5236, and the product will be the content in cubic feet. Then say, as one cubic foot is to the specific difference between... | |
| Zadock Thompson - 1832 - 182 páginas
...pyramid, its height heing 144 feet, and the sides of its base heing 5, 6 and 7 feet? Ans. 71.035+. 320. To find the solidity of a sphere.* RULE. — Multiply the cube of the diameter by .5236, or multiply the square of the diameter by one 6th of the circumference. 1. What ia the content of a... | |
| Zadock Thompson - 1832 - 186 páginas
...sides base 2J feet ? of its base being 5, 6 and 7 2£X2i=£X£=^=6£, feet?' Ans. 71.035+. Md 320. To find the solidity of a sphere.* RULE. — Multiply the cube of the diameter by .5336, or multiply the square of the diameter by one 6th of the circumference. 1. What is the content... | |
| Zadock Thompson - 1832 - 186 páginas
...24 feet? of its base being 5, 6 and 7 2iX2*=£X4=*ii=6i, feet? Ans. 71.035+. Ml 20.453125, Ans. 380. To find the solidity of a sphere.* RULE. — Multiply the cube of the diameter by ,52,16, or multiply the square of the diameter by one 6th of the circumference. •1. What ia the content... | |
| William Templeton (engineer.) - 1833 - 224 páginas
...Multiply the square of the diameter by 3.1416, the product will be the convex superficies. RULE 2. — Multiply the cube of the diameter by .5236, and the product is the solid content. EXAMPLE 1. — Required the convex surface of a sphere, whose diameter AB = 25| inches.... | |
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