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" If there is a remainder after the last division, write it after the quotient, or with the divisor under it as part of the quotient. PROOF. — Multiply the divisor by the quotient, and to the product add the remainder, if any. If the work is correct,... "
Elements of Arithmetic: For Primary and Intermediate Classes in Public and ... - Página 127
por William James Milne - 1893 - 240 páginas
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An Introduction to the Elements of Algebra: Designed for the Use of Those ...

Leonhard Euler - 1821 - 380 páginas
...remainder 5. 5 The following rule is to be observed in examples where there is a remainder. 54. If we multiply the divisor by the quotient, and to the product add the remainder, we must obtain the dividend; this is the method of proving division, and of discovering whether the...
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An Elementary Treatise on Arithmetic: Taken Principally from the Arithmetic of

Silvestre François Lacroix - 1825 - 394 páginas
...remainder 5. 5 The following rule is to be observed in examples where there is a remainder. 54. If we multiply the divisor by the quotient, and to the product add the remainder, we must obtain the dividend ; this is the method of proving division, and of discovering whether the...
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The Youth's Assistant in Theoretick and Practical Arithmetic

Zadock Thompson - 1826 - 176 páginas
...If this sum be less than the divisor, place a cipher in the quotient, and bring down another figure. Proof. Multiply the divisor by the quotient, and to the product add the remainder, if any, and if the sum equal the dividend, the work it right. Examples. 1. Divide 147 by 4. Having written...
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A brief compendium of arithmetic

Benjamin Snowden - 1835 - 108 páginas
...examples, and observe the manner of working them. Proof. — Multiply the Quotient by the Divisor, or the Divisor by the Quotient ; and to the Product, add the remainder, the sum will be the same as the Dividend if the work be right. Divisor. Dividend. Quotient. Divisor....
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A Theoretical and Practical Arithmetic: Designed for Common Schools and ...

Daniel Leach - 1851 - 280 páginas
...divide this number as before, and continue dividing in the same manner till all the figures are divided. PROOF. Multiply the divisor by the quotient, and to the product add the remainder, and if the sum be equal to the dividend, it is supposed to be right. OBS. 1. The dividend, divisor,...
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School Arithmetic: Analytical and Practical

Charles Davies - 1852 - 344 páginas
...there is a remainder, after dividing the last figure, set the divisor under it, and annex the result to the quotient. PROOF. — Multiply the divisor by the quotient, and to the product add the remainder, when there is one ; if the work is right the result will be equal to the dividend. / h EXAMPLES. (1.)...
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A Theoretical and Practical Arithmetic: Designed for Common Schools and ...

Daniel Leach - 1853 - 622 páginas
...divide this number as before, and continue dividing in the same manner till all the figures are divided. PROOF. Multiply the divisor by the quotient, and to the product add the remainder, and if the sum be equal to the dividend, it is supposed to be right. OBS. 1. The dividend, divisor,...
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Arithmetic, algebra, differential and integral calculus, by W. Rutherford ...

Royal Military Academy, Woolwich - 1853 - 476 páginas
...which were cut off from the dividend. 29. To prove Division. Multiply the quotient by the divisor, or the divisor by the quotient, and to the product add the remainder, if there be one. The result ought to be the same as the dividend ; because we are only adding the divisor...
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Greenleaf's Primary Arithmetic

Benjamin Greenleaf - 1854 - 156 páginas
...cipher in the quotient, and annex the next figure, 7, making 27, which contains the divisor 9 times. PROOF. — Multiply the divisor by the quotient, and to the product add the remainder, and if the result be like the dividend, the work is right. Thus : Quotient 15609 Divisor 4)1486 Dividend....
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Intuitive Calculations: The Most Concise Methods Ever Published, Designed ...

Daniel O'Gorman - 1856 - 186 páginas
...+ . 7.— What is the square root of 2-2710957 ? Ans. V50701 + . PROOF. — Square the root found, and to the product add the remainder, if any. If the work be right, the sum will be the same as the number to be extracted. Squares:—!, 4, 9, 16, 25, 36, 49,...
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