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Libros Libros 1 - 10 de 14 sobre Moreover, since any triangle whatever is equal to a right-angled triangle of the...
" Moreover, since any triangle whatever is equal to a right-angled triangle of the same base and altitude (Geom. 170), we can make use of the following simple rule, where the known parts admit of it, as equivalent to the foregoing; namely, the area of a... "
An Elementary Treatise on the Application of Trigonomentry to Orthographic ... - Página 89
por John Farrar - 1833 - 155 páginas
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An Elementary Treatise on the Application of Trigonometry: To Orthographic ...

John Farrar - 1822 - 153 páginas
...since any triangle whatever is equal to a rightangled triangle of the same base and altitude (Geoni. 170), we can make use of the following simple rule,...AB (fig. 65) = 12,38 ch., AC — 6,78 ch., and the angle Fig. 65. A = 46° 24' to find the area. 12,38 .... log 1,09272 6,78 .... log 0,83123 40° 24'...
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An Elementary Treatise on the Application of Trigonometry to Orthographic ...

John Farrar - 1822 - 153 páginas
...simple rule, where the known parts admit of it, as equivalent to the foregoing ; namely, the area nf a triangle is equal to the product of the base by half its altitude. Given AB (Jig. 65) = 12,38 ch., AC= 6,78 ch., and the angle Fig. 65. Jf = 46° 24' to find the area. 12,38 .......
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The new practical builder, and workman's companion, Volumen2

Peter Nicholson - 1823
...put A for their common altitude, and B, b, for their bases ; then BxA:fixA::B:5. THEOREM 53. 149. The area of a triangle is equal to the product of the base by half its altitude. For the triangle ABC is half the parallelogram ABCE, which has the same base, BC, and the same altitude...
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An Elementary Treatise on the Application of Trigonomentry to Orthographic ...

John Farrar - 1833 - 155 páginas
...its contiguous side = 11,46 ch., the included angle being 47° 30', to find the area. Ans. 12"- 3 r - 36P124. Since every parallelogram is divided by its...the area. 12,38 . . log. . . 1,09272 6,78 . . . log. . . . 0,83123 40° 24' . . log. sin . 9,85984 6,0,8986 1,78389 4 • 35944 40 14,37760 x Area = 6a-...
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Practical carpentry, joinery, and cabinet-making [by P. Nicholson. by P ...

Peter Nicholson - 1856 - 216 páginas
...their common altitude, and B, b, for their bases : then Bx A : их А :: B : b. THEOREM 44. 113. The area of a triangle is equal to the product of the base by half its altitude. For the triangle ABC is half the parallelogram ABCE, which has the same base, BC, and the same altitude...
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A course of geometrical drawing

William Schofield Binns - 1861
...applies to the triangles DEG, AEG; and, therefore, the triangle AFG is equal to AB c D E. Since the area of a triangle is equal to the product of the base multiplied by half its perpendicular height, (see Prob. 26 and Eue. I., 41), we can thus find the area...
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The Normal Standard Arithmetic: By Analysis and Induction, Designed for ...

Edward Brooks - 1895 - 415 páginas
...Altitude is a line perpendicular to the base drawn from the angle opposite; as, CD. Principle. — The area of a triangle is equal to the product of the base by one-half of the altitude. For it may readily be shown that the triangle ABC is J the parallelogram...
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First-year Mathematics for Secondary Schools

George William Myers, William Rockwell Wickes, Ernst Rudolph Breslich, Harris Franklin MacNeish, Ernest August Wreidt, Arnold B. Dresden - 1907 - 181 páginas
...altitude; ie, A =ba. Find.4,if (1) 6 = 13' ft, and a = 24 ft. ; (2) 6 = 10.2 in., and a=3.5 inches. 3. The area of a triangle is equal to ^ the product of the base by the altitude; ie, A = ^ ba. Find A, if (1) b = 12 ft., and a = 16 ft.; (2) 6=8.2 rd., and a = 7.78...
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First-year Mathematics for Secondary Schools

George William Myers - 1909 - 365 páginas
...is, A =6a. Find A, if (1) 6 = 13 ft., and « = 24 feet; (2) 6 = 10.2 in., and a=3.5 inches. 3. The area of a triangle is equal to \ the product of the base by the altitude; that is, A = \ba. Find A, if (1) 6 = 12 ft., and a = 16 feet; (2) 6=8.2 rd., and a=7.78...
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The Gilbert Arithmetics, Libro 3

Charles H. Gleason, Charles Benajah Gilbert - 1910
...previous lessons, the following rules for finding the areas of plane figures have been learned : 1. The area of a triangle is equal to | the product of the base by the altitude. 2. The area of a rectangle is equal to the product of the length by the breadth. 3. The...
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