...by the units. Th e product of th e tent by the square of the mat. 2D. The square of the tens, Ttcice the product of the tens by the units, The square of the units, ' being multiplied by the units, will gire f The product of the iquare of the tens multiI /I//C/ by...

...will thence result, let us give to this feigned operation the following form : 1st, The cube of the The square of the tens, Twice the product of the tens by the units, The square of the units, being multiplied the tens, will . gye tens. Twice the product of the square of the tens multiplied...

...the tens in any number, and b the units, we shall have, for the square of a + b, a3 + 2ab + b ; that is, the square of the tens, twice the product of the tens by the units, plus the square of the units. Let a = 8, and 6 = 5: then, since a represents the tens, and b the units,...

...the units place in the divisor. Multiplying the divisor, so increased, the product will be the double product of the tens by the units, + the square of the units ; for, 5 x 165 is the same as 5 x 160 + 5 x 5, or 5 times 16 tens, -j- 5 times 5 units. If 5 x 165...

...square of OPERATION. 20 7 20 7 400 140 140 49 400 280 49 a number containing two figures, consists of the square of the tens, twice the product of the tens by the units, and the square of the units. Now the square of 10 is 100, the square of 100 is 10000, the square of...

...writing each product separately, instead of adding them as we proceed. We then 4^ see that we must add the square of the tens, twice the ^'product of the tens by the units, and the square of the 21 units. •'_ 1369 Let us now reverse the process, and extract the square root...

...writing each product separately, instead of adding them as we proceed. We then ( ^ see that we must add the square of the tens, twice the •* product of the tens by the units, and the square of the ~* units. _1^ 1369 Let us now reverse the process, and extract the square root...

...each product sepa- — rately, instead of adding them as we proceed. We then 49 see that we must add the square of the tens, twice the **• product of the tens by the units, and the square of the ^1 units. •' 1369 Let us now reverse the process, and extract the square root...

...the hundreds by the tens; + square of the tens; + twice the product of the hundreds by the units ; + twice the product of the tens by the units; +the square of the units. Let us consider 576 as a root, then will its square consist of " The square of the hundreds," 5002 = 250000...

...the hundreds by the tens; + square of the tens; + twice the product of the hundreds by the units ; + twice the product of the tens by the units; +the square of the units. Let us consider 576 as a root, then will its square consist of " The square of the hundreds," 500 2 = 250000...