| Charles Davies - 1830 - 390 páginas
...off two places for decimals, the number to be added is 56.55. This number being added to 5.827886, gives 5.827942 for the logarithm of 672887 ; the decimal...rigorously true. In the example, the logarithm of 672800 is 5.827886 ; of 672900, a number greater by 100, 5.827951 : the difference of the logarithms is 65. Now,... | |
| Robert Gibson - 1833 - 436 páginas
...off two places for decimals, the number to be added is 56.55. This number being added to 5.827886, gives 5.827942 for the logarithm of 672887 ; the decimal...rigorously true. In the example, the logarithm of 672800 is 5.827886 ; of 672900, a number greater by 100, 5.827951 : the difference of the logarithms is 65. Now,... | |
| Adrien Marie Legendre - 1836 - 394 páginas
...for decimals, the number to be added is 56.55. This number being added to 5.827886, gives 5.827912 for the logarithm of 672887 ; the decimal part .55,...rigorously true. In the example, the logarithm of 672800 is 5.827886 ; the logarithm of 672900, a number greater by 100, 5.827951 : the difference of the logarithms... | |
| Adrien Marie Legendre - 1837 - 376 páginas
...off two places for decimals,. the number to be added is 56.55. This number being added to 5.827886, gives 5.827942 for the logarithm of 672887; the decimal...rigorously true. In the example, the logarithm of 672800 is 5.827886 ; the logarithm of 672900, a number greater by 100, 5.827951 : the difference of the logarithms... | |
| Adrien Marie Legendre - 1838 - 382 páginas
...off two places for decimals, the number to be added is 56.55. This number being added to 5.827886, gives 5.827942 for the logarithm of 672887 ; the decimal...omitted. This method of finding the logarithms of numl.ers, from the table, supposes that the logaiithms are proportional to their respective numbers,... | |
| Charles Davies - 1849 - 372 páginas
...off two places for decimals, the number to be added is 56.55. This number being added to 5.82788Ci, gives 5.827942 for the logarithm of 672887 ; the decimal...omitted. This method of finding the logarithms of numl ers, from the table, supposes that the loganthms are proportional to their respective numbers,... | |
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