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12 feet 9 inches ABCD abscissa ADBA altitude Avoirdupois base Bisect breadth cask centre chord of half circumference cone conjugate diameter cube root cubic inches cylinder decimal Demon diagonal distance divided draw the line ellipse equal EXAMPLES feet 6 inches feet 9 figure find the area find the solidity fluxion foot fraction frustrum girth give the solidity given line greater end half the arc head diameter horse power hyperbola length less end linear side measure minute ordinate parabola parallel pentagon plane polygon PROBLEM proportion pyramid quotient radius regular polygon Required the area Required the solidity revolutions per minute right angled right line segment sine of half slant height SLIDING RULE solid content specific gravity sphere spheroid square feet square root superficies thickness transverse diameter trapezium triangle ullage velocity versed sine water wheel wheel wine gallons yard
Página 16 - A sector is any part of a circle bounded by an arc, and two radii drawn to its extremities. A quadrant, or quarter of a circle...
Página 20 - In a right-angled triangle, the side opposite to the right angle, is called the hypothenuse ; and the other two sides are called the legs, and sometimes the base and perpendicular : thus, A, B is the base, B, C perpendicular, and A, C hypothenuse.
Página 19 - Parallel straight lines are such as are in the same plane, and which, being produced ever so far both ways, do not meet.
Página 125 - To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity.
Página 21 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Página 66 - Ans. 20.3718. troublesome and laborious that it must have cost him incredible pains. It is said to have been thought so curious a performance, that the numbers were cut on his tomb-stone in St. Peter's Church-yard, at Leyden.
Página 96 - As the conjugate diameter is to the transverse, So is the square root of the difference of the squares of the ordinate and semi-conjugate, To the distance between the ordinate and centre.
Página 157 - To find the solidity of an hyperboloid. RULE.* To the square of the radius of the base add the square of the middle diameter between the base and the vertex ; and this sum multiplied by the altitude, and the product again by .5236, will give the solidity.