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" Multiply the last remainder by the first divisor, and to the product add the first remainder ; the sum will be the true remainder. "
Adams's Improved Arithmetic: Arithmetic, in which are Combined the Analytic ... - Página 38
por Daniel Adams - 1861 - 280 páginas
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Carleton's Compendium of Practical Arithmetic: Applied to the Federal and ...

Osgood Carleton - 1810 - 264 páginas
...there be a remainder in one, or both operations, multiply the first divisor by the last remainder ; to the product add the first remainder, the sum will be the true remainder. • EXAMPLES. 1 Divide 120456 by 21. 2 Divide 59Г364 by 35. 3 times 7 3)120456 5 times 7 5)597364...
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A Complete System of Theoretical and Mercantile Arithmetic: Comprehending a ...

George G. Carey - 1818 - 602 páginas
...divisors instead of one, if there should be any remainder in dividing by the second figure, multiply this remainder by the first divisor, and to the product add the first remainder (if any) and the sum will be the complete remainder*. * If there be no reminder in dirieing by the...
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The Arithmetical Catechism, Compiled from Various Authors, for the Use of ...

Henry Jackson - 1824 - 172 páginas
...tkercbc a remainder in the first or last division, or both, how •will you find the true remainder ? A. Multiply the last remainder by the first divisor, and to the product add the tii-st remainder, if any, and it will give the true one. NOTE. — Should there be no remainder in...
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A treatise on mercantile and practical arithmetic

John Penrose (teacher of arithmetic.) - 1824 - 320 páginas
...division, must be strictly observed, when determining the fractional parts, that is, to multiply the second remainder by the first divisor, and to the product add the first remainder. When there are three component parts, multiply the third remainder by the second divisor, and to the...
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An introduction to arithmetic; or, The teacher's ease and scholar's help

Introduction - 1830 - 102 páginas
...@2。。) ' 2 グ . ; タ 2 (28]) : アガタダコダダ 、 ' + グクククク NOTE. When there are two Divisors, multiply the last Remainder by the first Divisor, and to that Product add the first Remainder, which will give the true one.When there are more than two Divisors,...
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A New System of Arithmetick: In which the Rules are Familiarly Demonstrated ...

William Ruger - 1832 - 282 páginas
...parts of the divisor, and then that quotient by tie other. How do you find the true remainder ? A. Multiply the last remainder by the first divisor, and to the product add the first remainder, and it wul give the true remainder. If your divisor be eight ?,rhat would you. call the component parts?...
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The North American Arithmetic: Uniting Oral and Written Exercises, in ...

Frederick Emerson - 1833 - 198 páginas
...32 the divisor; what is the quotient? To obtain the true remainder, where factors have been used as divisors, multiply the last remainder by the first...divisor, and to the product add the first remainder. 27. Suppose 622 to be a dividend, and 35 the divisor; what is the quotient; and what the remainder...
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The North American Arithmetic: Part Second, Uniting Oral and Written ...

Frederick Emerson - 1832 - 344 páginas
...32 the divisor; what is the quotient? To obtain the true remainder, where factors have been used as divisors, multiply the last remainder by the first...divisor, and to the product add the first remainder. 27. Suppose 622 to be a dividend, and 35 the divisor; what is the quotient; and what the remainder...
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The North American Arithmetic: Part Third, for Advanced Scholars, Volumen3

Frederick Emerson - 1834 - 300 páginas
...quotient thence arising by the other: the last quotient will be the true one. To find the true remainder, multiply the last remainder by the first divisor, and to the product add the first remainder. 1. Divide 4062900311 by 9, and prove the operation. 2. How many times is 502 contained in 74260710?...
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The North American Arithmetic: Part Third, for Advanced Scholars

Frederick Emerson - 1835 - 300 páginas
...quotient thence arising by the other: the last quotient will be the true one. To find the true remainder, multiply the last remainder by the first divisor, and to the product add the ftrst remainder. 1. Divide 4062900311 by 9, and prove the operation. 2. How many times is 502 contained...
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