 Hence, the area of a triangle is equal to one-half the product of any two sides ' and the sine of their contained angle. EXAMPLES. 1. Find the area of the triangle in which two sides are 31 ft. and 23 ft. and their contained angle 67° 30'.  Plane Trigonometry - Página 221906 - 188 páginasVista completa - Acerca de este libro
 | Eugene Lamb Richards - 1880 - 108 páginas
...produced. CD = b sin. A. ((1) Art. 30), (Art. 46). Area = $cxCD (Ch. 5, IV.), = $ bo sin. A. Therefore, the area of a triangle is equal to one-half the product of any two adjacent sides multiplied by the sine of the included angle. Suppose c and the angles A and B are given.... | |
 | Daniel Alexander Murray - 1899 - 226 páginas
...= £ bo sin (180 — A). -i* ; It will be seen in Art. 45, that sin (180 — A) = sin A. Hence, the area of a triangle is equal to one-half the product of any two sides and the sine of their contained angle. EXAMPLES. 1. Find the area of the triangle in which two sides are 31 ft. and 23 ft.... | |
 | International Correspondence Schools - 1906 - 634 páginas
...= f sin A. The substitution of this value of h in the formula in Art. 26 gives , , , S = a be sin A In words, the area of a triangle is equal to one-half...chains, respectively, and their included angle is 65° 10* 40". To find the contents of the field, in acres. SOLUTION.— By the formula, 5 (square chains)... | |
 | Daniel Alexander Murray - 1906 - 466 páginas
...= \AB- DC; = \ be aw (180 -A). It will be seen in Art. 45, that sin (180 — A) = sin A. Hence, the area of a triangle is equal to one-half the product of any two sides and the sine of their contained angle. EXAMPLES. 1. Find the area of the triaugle in which two sides are 31 ft. and 23 ft.... | |
 | Daniel Alexander Murray - 1908 - 358 páginas
...• DC-, = \bc sin (180 — A). It will be seen in Art. 45, that sin (180 — A) = sin A. Hence, the area of a triangle is equal to one-half the product of any two sides ' and the sine of their contained angle. EXAMPLES. 1. Find the area of the triangle in which two sides are 31 ft. and 23 ft.... | |
 | Frank Castle - 1908 - 616 páginas
...height. As any side may be considered as the base of a triangle, the rule may be stated thus : the area of a triangle is equal to one-half the product of any side of a triangle and the length of the perpendicular let fall on that side from the opposite angle.... | |
 | Alfred Monroe Kenyon, Louis Ingold - 1913 - 300 páginas
...have p = b sin A, and A. = (1/2)pc = (1/2) be sin A, ie the area of a triangle is equal to one half the product of any two sides and the sine of their included angle. (2) Given two angles A, C, and their included side b. Solve the triangle by Case I to find B and one... | |
 | Alfred Monroe Kenyon, William Vernon Lovitt - 1917 - 384 páginas
...p = b sin A Fia. 59 and (48) Area = I be sin A, whence, the area of a triangle is equal to one half the product of any two sides and the sine of their included angle. If the three sides are given, a formula for the area can be deduced from (48) as follows. From (26),... | |
 | Alfred Monroe Kenyon, Louis Ingold - 1919 - 306 páginas
...one of the given sides, as p upon b, then p = a sin C and by (1) A = £ b (a sin C) ; whence (2) The area of a triangle is equal to one-half the product of any two sides into the sine of their included angle. 53. Area from Three Sides. If A the three sides are given, draw... | |
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