 | Roswell Chamberlain Smith - 1814 - 300 páginas
...Hence, Шеп the flitretnes, ami the Number of Term«, ft given, loßnd the Sum of all the Terms;— Multiply half the sum of the extremes by the number of terms, and the product will be the answer. in. If the ertiemes be 3 and 373, and the number of terms 40, what... | |
 | B. M. Tyler - 1827 - 308 páginas
...series. RULE. Multiply the sum of the extremes by the number of terms, and divide the product by 2 ; or multiply half the sum of the extremes by the number of terms. 1 1. If the first term of an arithmetical series be 2, the last term 122, and the number of terms 29,... | |
 | Samuel Read Hall - 1832 - 294 páginas
...Ans. RULE 4. When the first, last and number of terms are given, to find the sum of all the terms or series, — Multiply half the sum of the extremes by the number of terms, and the product will be the answer. GEOMETRICAL PROGRESSION. By Geometrical Progression is meant, a... | |
 | Zadock Thompson - 1832 - 186 páginas
...IV. The first and last term, and the number of terms given to find the sum of the series. RULE. — Multiply half the sum of the extremes by the number of terms, and the product will be the sum of the series. 2. How many times does a common clock strike in 12 >ours?... | |
 | Zadock Thompson - 1832 - 186 páginas
...IV. The first and last term, and the number of terms given to find the sum of the series. ROLE. — Multiply half the sum 'of the extremes by the number of terms, and the product will be the sum of the series. 2. How many times does a common clock strike in 12 hours?... | |
 | Charles Guilford Burnham - 1837 - 266 páginas
...When the first and last terms, and the number of terms are given, to find the sum of the series. RULE. Multiply half the sum of the extremes by the number of terms ; the product will be the sum of the series. 14. A man has 9 sons; the youngest is 8, the eldest 40... | |
 | Roswell Chamberlain Smith - 1839 - 308 páginas
...l*ence, JHien the Extremes, and the Number of Terms, cat given, to find the Sum of all the Terms ; — Multiply half the sum of the extremes by the number of terms, and the product will be the answer. 10. [f the extremes be 3 and 273, and the number of terms 40, what... | |
 | Calvin Tracy - 1840 - 316 páginas
...35 cents, average price ; hence, 30x35 = $10.50, whole cost. We have the following rule : RULE. — Multiply half the sum of the extremes by the number of terms ; the product will be the answer. Z. Paid 4 cents for the first, and $1.21 for the last yard of a piece... | |
 | Roswell Chamberlain Smith - 1841 - 324 páginas
...Hence, when the extremes, and the number of terms, are given, to find the sum of all the terms. — Multiply half the sum of the extremes by the number of terms, and the product will be the answer 22. If the extremes be 3 and 273, and the number of terms 40, «... | |
 | William Ruger - 1841 - 268 páginas
...term, common difference, and the number of terms given, to find the sum of all the terms. RULE. — Multiply half the sum of the extremes by the number of terms, and the product will be the ansver or sum of all the terms. EXAMPLES. 1. A person bcught 16 yards of... | |
| |
To find the sum of an arithmetical series : Multiply half the sum of the extremes by the number of terms. 
