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" RULE. — From half the sum of the three sides subtract each side separately ; multiply the half -sum and the three remainders together ; the square root of the product is the area. "
Geometry: Plane Trigonometry. Chain Surveying. Compass Surveying. Transit ... - Página 20
por International Correspondence Schools - 1906
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A Treatise of Practical Surveying: Which is Demonstrated from Its First ...

Robert Gibson - 1806 - 452 páginas
...following problem will be evident. PROBLEM VIII. Three sides of a plane triangle given t0 find the area. RULE. From half the sum of the three sides subtract each side severally ; take the logarithms of half the sum and three remainders, anil half their total will be...
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An Introduction to the Theory and Practice of Plane and Spherical ...

Thomas Keith - 1810 - 420 páginas
...these four logarithms, is the logarithmical sine of half the angle sought. (H. 215.) OR, RULE III. From half the sum of the three sides subtract each side separately. Then add together, The logarithmica! co-secants of half the sum of the sides, and of the difference...
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The Description and Use of the Sliding Rule, in Arithmetic, and in the ...

Andrew Mackay - 1811 - 138 páginas
...easily measured by the above method. In this case, therefore, the three sides are to be measured. Now from half the sum of the th'ree sides, subtract each side separately; then extract the square root of the product of half the sum of the sides by the three differences ;...
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The Theory and Practice of Surveying: Containing All the Instructions ...

Robert Gibson - 1811 - 508 páginas
...following problem will be evident. PROB. nil. The three sides of a filane triangle given to find the area. RULE. From half the sum of the three sides subtract each side severally ; take the logarithms of half the sum and three remainders, and half their total will be...
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A Treatise on Surveying, Containing the Theory and Practice: To which is ...

John Gummere - 1814 - 346 páginas
...48° 15'? Ans. 6A. 3R. 18P. PROBLE To find the area of a triangle, when the three sides are. given. % RULE; From half the sum of the three sides subtract each side severally ; multiply the half sum and the three remainders contiuually together, and the square root...
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A Treatise on Practical Surveying: Which is Demonstrated from Its First ...

Robert Gibson - 1818 - 478 páginas
...problem will be evident. PROB. VIII. Tlie three sides of a plane triangle given, to find the area. RULE. From half the sum of the three sides subtract each side severally ; take the logarithms of the half sum and three remainders, and half their total will be...
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A treatise of practical mensuration

Anthony Nesbit - 1824 - 434 páginas
...£6 4*. 7 \d. , PROBLEM V. To find the area of a triangle, the three sides only of which are given. RULE. From half the sum of the three sides subtract each side severally ; multiply the half sum and the three remainders continually together; and the square root...
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An Introduction to the Theory and Practice of Plain and Spherical ...

Thomas Keith - 1826 - 442 páginas
...these four logarithms, is the logarithmical sine of half the angle sought. (F. 184.) OR, RULE III. From half the sum of the three sides subtract each side separately. Then add together, The logarithmical co-secants of half the sum of the sides, and of the difference...
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A Short System of Practical Arithmetic: Compiled from the Best Authorities ...

William Kinne - 1829
...true right-angle. RULE 2. — To find the area of any triangle when the three sides only are given, RULE. — From half the sum of the three sides' subtract each side severally ; multiply these three remainders and the said half sum continually together; then the square...
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The Teacher's Assistant, and Scholar's Mathematical Directory: Containing ...

Dudley Leavitt - 1830 - 109 páginas
...the three sides of a triangle are given, the area may be found thus, without a perpendicular. Erom half the sum of the three sides, subtract each side separately ; multiply the half sum and 3 remainders continually together, and the square root of the last product will be...
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