 | Samuel YOUNG (of Manchester.) - 1833 - 272 páginas
...of the Products by three times the sura of the whole weight; the square root of the Quotient will be the distance of the centre of gyration from the centre of motion. (1) A bar, of uniform density, 12 feet long, and each foot weighing 7 Ibs. and revolving upon a centre... | |
 | Luke Hebert - 1835 - 816 páginas
...the sum of the products by the weight of the whole mass, and the square root of the quotient will be the distance of the centre of gyration from the centre of motion. CENTRE OF OSCILLATION is that point in a body suspended from a point and made to vibrate, in which... | |
 | William Grier - 1836 - 384 páginas
...from the centre, to generate that velocity? 6 X 2 X 10 120 = = -1562 of a t0" = 3 cwt. 1-49G rWhat is the distance of the centre of gyration from the centre of motion of a fly-wheel, the force which moves the wheel being 2 cwt., acting at the distance of 7 feet from the... | |
 | Luke Hebert - 1836 - 814 páginas
...the sum of the products by the weight of the whole mass, and the square root of the quotient will be the distance of the centre of gyration from the centre of motion. CENTRE OF OSCILLATION is that point in a body suspended from a point and made to vibrate, in which... | |
 | William Grier - 1842 - 320 páginas
...must be applied for 8 seconds, at the distance of 3 feet from the centre, to generate that velocity ? What is the distance of the centre of gyration from the centre of motion of a fly-wheel, the force which moves the wheel being 2 cwt., acting at the distance of 7 feet from the... | |
 | W. H. CRANK - 1843 - 340 páginas
...the centre of gyration is = 18 x -6324= 11-3832 inches. (2) There is a rod 82'3 inches long. Required the distance of the centre of gyration from the centre of motion. Ans. 47-32825 inches. It was intended to have introduced a short treatise on the Mechanical Powers... | |
 | Charles Haynes Haswell - 1844 - 298 páginas
...upon a lever (which is here assumed to be without weight) at the respective distances of 1 and 2 feet, what is the distance of the centre of gyration from the centre of motion (the fulcrum) ? 3X12 = 3. = = 2.71, and .^2.71 = 1.64 feet, Ana. That is, a single weight of 7 Ibs.,... | |
 | Artizan club (London, England) - 1847 - 338 páginas
...ascertained. ID a right line, or a cvlinder of very small diameter revolving about one of its extremities, the distance of the centre of gyration from the centre of motion is equal to the length of the revolving Tine or cylinder multiplied by the Hjuare root of I. In the... | |
 | Charles Haynes Haswell - 1851 - 346 páginas
...upon a lever (which is here assumed to he without weight) at the respective distances of 1 and 2 feet, what is the distance of the centre of gyration from the centre of motion (the fulcrum) 1 3. 4X2= = 16. — = 2.71, and ^2.71 = 1.64 feet, Ans. That is, a single weight of 7... | |
 | Oliver Byrne - 1851 - 310 páginas
...ascertained. In a right line, or a cylinder of very small diameter revolving about one of its extremities, the distance of the centre of gyration from the centre of motion is equal to the length of the revolving line or cylinder multiplied by the square root of J. In the... | |
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... the square root of the quotient will be the distance of the centre of gyration, from the centre of motion. 
