| Robert Simson - 1775 - 520 páginas
...by twice the rectangle CB, BD. A Secondly, Let AD fall with- A. out the triangle ABC : Then, becaufe **the angle at D is a right angle, the angle ACB is greater** d than a right angle ; . and therefore the fquare of AB is equal c to the fquares of AC, CB, and twice... | |
| Euclid - 1781 - 520 páginas
...by twice the reelangle CB, BD. becondly, Let AD fall with- ' A. out the triangle ABC : Then, becaule **the angle at D is a right angle, the angle ACB is greater " than a right angle** ; and therefore the fquare of AB is equal c to the fquaies of AC, CB, and twice the rectangle BC, CD:... | |
| Robert Simson - 1781 - 466 páginas
...AC, and twice the rectangle CB, BD ; that is, the fquare of AC alone is lefs than the fquares of CB, **BA by twice the rectangle CB, BD. Secondly, Let AD fall without the triangle ABC. then** becaufe the angle at D is a right angle, the angle ACB is greater d than a right angle ; and therefore... | |
| John Playfair - 1795 - 400 páginas
...BA by twice the reftangle CB, BD. Secondly, " Let AD fail without the triangle ABC : Then, becaufe **the angle at D is a right angle, the angle ACB is greater** d than a iight angle; and therefore the j ,5 1. fquare of AB is equal e to the fquares of AC, CB, and... | |
| Euclid, John Playfair - 1804 - 440 páginas
...AC2 is lefs than BC2+ AB2 by 2BC.BD. Secondly, Let AD fall without the triangle ABC * : Then becaufe **the angle at D is a right angle, the angle ACB is greater* than a right angle,** and AB2 — e AC2+BC2-)-2BC.CD. Add BC2 to each ; then AB2+BC2— AC2+2BC2+2BC.CD. But aii-ib 7. i.... | |
| Robert Simson - 1804
...AC, and twice the rectangle CB, BD; that is, the fquare of AC alone is lefs than the fquares of CB, **BA by twice the rectangle CB, BD. Secondly, Let AD fall without the triangle ABC. then** becaufe the angle at D is a right angle, the a,ngle ACB is greater d than a right angle; and therefore... | |
| John Playfair - 1806 - 311 páginas
...BDS+AD2=AB», and CD* +DAZ=CAC*; therefore BC2+ AB2=2BC.BD+AC2; that is, AC2 is less than BC2+ABS by 2BC.BD. **Secondly, let AD fall without the triangle ABC* ;...the angle at D is a right angle, the angle ACB is** greater11 than a right angle, and AB*=e AC2-)-BC2+2BC.CD. d 16. 1. Add BCz to each ; then ABS+BC2=AC24^BC?£2BC.CD.... | |
| Robert Simson - 1806 - 518 páginas
...less than the squares of CB, BA by twice the rectangle CB, BD. Secondly, Let AD fall with- - A out **the triangle ABC : then, because the angle at D is a right // ' angle, the angle ACB is greater** // ' d 16. 1. d ihan a right angle ; and there e 12. 2. fore the square of AB is equal* to the squares... | |
| Euclid - 1810 - 518 páginas
...that is, the square of AC alone is less than the squares of CB, BA by twice the rectangle CB, BD. A **Secondly, Let AD fall without the triangle ABC : then,...angle at D is a right angle, the angle ACB is greater** d 16. 1. •'•. than a right angle ; and theree 12. 2. fore the square of AB is equal « to the squares... | |
| Euclides - 1814
...AC, and twice the rectangle CB, BD, that is, the square of AC alone is less than the squares of CB, **BA by twice the rectangle CB, BD. Secondly, Let AD...angle at D is a right angle, the angle ACB is greater** d than a right angle ; and therefore the square of AB is equal e to the squares of AC, CB,and twice... | |
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