 | John Playfair - 1855 - 350 páginas
...; and in AC take any point D, and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be cut off from it ; join BC, and draw DE parallel to it: th«n AE is the part required to be cut off. Because CD is parallel to one of the sides of the triangle... | |
 | Euclid, Isaac Todhunter - 1867 - 426 páginas
...any part required. Let AB be the given straight line : it is required to cut off any part from it. From the point A draw a straight line AC, making any angle with AB; in AC tak e any point D, and take AC the same multiple of AD, that AB is of the part which is to be... | |
 | Robert Potts - 1868 - 434 páginas
...off any part required, Let AB be the given straight line. It is required to cut off any part from it. From the point A draw a straight line AC, making any...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
 | Euclides - 1874 - 342 páginas
...required to cut off any part from it. Construction. From the point A draw a straight line AC, making «ny angle with AB ; and in AC take any point D, and take...AC the same multiple of AD, that AB is of the part whi•-' :s to be cut off from it ; join BC, and draw D£ parallel to CB. B< Then AE shall be the part... | |
 | Euclid - 1876 - 240 páginas
...PROBLEM. From a given finite straight line (AB) to cut off any required part, or submultiple. SOLUTION. From the point A draw a straight line AC, making any...from it ; join BC, and draw DE parallel to it : then AK is the part required to be cut off. fa) VL 2. (6) V. 18. (c$ VD DEMONSTRATION. Because ED is parallel... | |
 | Robert Potts - 1876 - 446 páginas
...off any part required. Let AB be the given straight line. It is required to cut off any part from it. From the point A draw a straight line AC, making any...angle with AB\ and in AC take any point D, and take ACtiie same multiple of AD, that AB is of the part which is to be cut off from it ; join BG, and draw... | |
 | Isaac Sharpless - 1879 - 282 páginas
...any point D, and take AC so that it shall contain AD as many times as AB is to contain the part that is to be cut off from it; join BC, and draw DE parallel to it; then AE is the part to be cut off. Because ED is parallel to one of the sides of the triangle ABC (V. 2), CD : DA :: BE... | |
 | Isaac Todhunter - 1880 - 426 páginas
...cut off any part from it. From the point A draw a straight line AG, making any angle with AB; in AG take any point D, and take AC the same multiple of...off from it ; join BC, and draw DE parallel to it. AE shall be the part required to be cut off. For, because ED is parallel to BC, [Construction. one... | |
 | Euclides - 1881 - 236 páginas
...point A draw a straight line AC, making any A angle BAC, with AB. In AC take any point D, and make AC the same multiple of AD, that AB is of the part to be cut off from it Join BC, and draw DE parallel to E/-AB C B. The part AE is the part required... | |
 | Isaac Sharpless - 1882 - 286 páginas
...point D, and from the point D along the line DC lay off AD the given number of times, to the point C; join BC, and draw DE parallel to it ; then AE is the part to be cut off. Because ED is parallel to one of the sides of the triangle ABC (V. 2), CD : DA : : BE... | |
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From the point A draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required... 
