 | Thomas Tate (mathematical master.) - 1848 - 284 páginas
...whole surface. Ans. 1061 c.ft. and 643-2 sq.ft. 21. PROBLEM. To find the solidity of a wedge. EULE. To twice the length of the base, add the length of the edge, multiply this sum by the product of the breadth of the base and the height of the wedge, and ^ of the... | |
 | Rufus Putnam - 1849 - 276 páginas
...12J cubic feet to weigh a ton, 2000 pounds ? 175. To FIND THE SURFACE AND SOLID CONTENT OF A WEDGE. RULE FOR THE SURFACE. Find the areas of the rectangle,...multiply the sum by the breadth of the base, and by one sixth of the perpendicular from the edge upon the base ; the product will be the content. 28. Required... | |
 | Rufus Putnam - 1849 - 402 páginas
...12 J cubic feet to weigh a ton, 2000 pounds ? 175. To FIND THE SURFACE AND SOLID CONTENT OF A WEDGE. RULE FOR THE SURFACE. Find the areas of the rectangle,...FOR THE SOLID CONTENT. To twice the length of the liase add the length of the edge, and multiply the sum by the breadth of the base, and by one sixth... | |
 | Thomas Kelt - 1849 - 424 páginas
...95-8188 cubic feet, and X 6-232 = 597-1427 gallons. To find the solid contents of a wedge. Ride. — To twice the length of the base add the length of the edge ; multiply the sum by the breadth of the base, and by the perpendicular height from the base, and one... | |
 | John Radford Young - 1850 - 294 páginas
...being 56-5488 feet. Ans. 7572-98 Feet. PROBLEM VI. — To find the solid content of a wedge. RULE. To twice the length of the base add the length of the opposite edge ; mtdtiply the sum by the breadth of the base, and that product by the perpendicular... | |
 | Joseph Bateman - 1852 - 376 páginas
...the hcight, and by the breadth of the base, and one sixth of that product will be the content. II. To twice the length of the base, add the length of...by the breadth of the base, and by one-sixth of the hcight ; the product will be the solid content. * To find the superficics of any regular body, multiply... | |
 | Gerardus Beekman Docharty - 1867 - 474 páginas
...and pyramid. .-. vol. of wedge = %bh(2l+ 1), the same as above. Hence we derive the following RULE. To twice the length of the base add the length of the edge, and multiply the sum by one sixth of the product of the height of the wedge and breadth of the base. EXAMPLE. What is the volume... | |
 | Daniel Kinnear Clark - 1878 - 1022 páginas
...multiply the sum by 7854, and by one-third of the height To find the cubic contents of a wedge. — To twice the length of the base add the length of the edge ; multiply the sum by the breadth of the base, and by one-sixth of the height. To find the cubic contents... | |
 | Michael McDermott - 1879 - 540 páginas
...33 — 27 — 8 19 D — d 3 — 2 ~T Tabular number per Table One-third the length S CANALS. Rule^ To twice the length of the base add the length of the edge, multiply this sum by the breadth of the base, and the product by one-sixth of the height, the product... | |
 | 1880 - 754 páginas
...ft-, and 2 (5 ft. 4 in-)+(3 ft. 6 te.)=2m+n=Jyfc ft. .-. the sol. of the wedge =/rXV=4TW cu- ftRule : To twice the length of the base add the length of the edge, and multiply the sum by the altitude and width of the base, and take one sixth of the product. CORNELIUS DILLY. 8. If it takes... | |
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To twice the length of the base add the length of the edge ; multiply the sum by the breadth of the base, and by one-sixth of the height. 
