 | Ellis A. Davidson - 1869 - 136 páginas
...construct an Oblong equal to it in area. 33. What is meant by Parallel Lines ? 34. Show by a Drawing that " Triangles upon the same Base and between the same Parallels are equal." 35. Draw any Triangle, and another equal to six of the first added together. 36. Fill a Square with.... | |
 | Euclides - 1870 - 270 páginas
...two points. P. 31. Through a given point to draw a st. line parallel to a given st. line. DEM. — P. 37. Triangles upon the same base and between the same parallels are equal. Ax. 1. Magnitudes equal to the same magnitude are equal. EXP. 1 HypConcl. Let the AS ABC, DEC, A be... | |
 | Euclides - 1871 - 136 páginas
...[3EBCH= EJEFGH, i. 35. V they are on the same base EH and between the same IIs ; .-. O ABCD =o EFGH. Triangles upon the same base, and between the same parallels, are equal to one another. Let A s ABC, DBC be on same base BC and between same lis AD. BC. Then must &ABC= &DBC. From B draw... | |
 | Henry William Watson - 1871 - 320 páginas
...proved equal to the area of AF, therefore the area of AF is equal to the area of GD. PROPOSITION 6. Triangles upon the same base and between the same parallels are equal to one another in area. Fig. 14. j) AD P Let the triangles ABC and DBC be upon the same base BC, and between the same... | |
 | William Kennedy Maxwell - 1871 - 148 páginas
...ft. 13. Here, as 4-1 : 65 : : 5 : 79-26, the height of the pole. Ans. 14. Now, triangles that stand upon the same base, and between the same parallels are equal to each other ; therefore, this question will, as shown in the figure, admit of two answers. Here, the... | |
 | Euclides, James Hamblin Smith - 1872 - 376 páginas
...CJEFGH, i. 35. v they are on the same base EH and between the same IIs ; QED PROPOSITION XXXVII. THEOREM. Triangles upon the same base, and between the same parallels, are equal to one another. Let A s ABC, DBC be on same base BC and between same IIs AD, BC. Then must &ABC= A DBC. From B draw... | |
 | Euclid, Charles Peter Mason - 1872 - 216 páginas
...ABCD and EFGH, being each equal to the parallelogram ABGH, Are equal to each other. PBOPOSITION XXXVU. Triangles upon the same base and between the same parallels are equal to each other. For the construction in this proposition we must be ableto draw a straight line from a... | |
 | Hugo Reid - 1872 - 148 páginas
...produced. 142. If ote. — This illustrates the important geometrical truth, that — Parallelograms on the same base and between the same parallels are equal to one another; that is, equal in area. Fic.34 AEFD and ABCD are on the same base AD and between the same parallels... | |
 | Lewis Sergeant - 1873 - 182 páginas
...decimals. (10.) 21 41 21 228 2000 _1824 1~7G, <fcc. (See Arith., § 61.) * 3. Show that parallelograms and triangles upon the same base and between the same parallels are equal to one another. (10.) (This appears to mean that parallelograms on the same base and between the same parallels are... | |
 | Edward Atkins - 1874 - 426 páginas
...Therefore the parallelogram ABCD is equal to the parallelogram EFGH (Ax. 1). Proposition 37. — Theorem. Triangles upon the same base, and between the same parallels, are equal to one another. Let the triangles ABC, DEC be on the same base BC, and between the same parallels AD, BC ; The triangle... | |
| |
TRIANGLES upon the same base, and between the same parallels, are equal to one another. 
