Hidden fields
Libros Libros
" Divide the coefficient of the dividend by the coefficient of the divisor. "
An Elementary Treatise on Algebra: For the Use of Students in High Schools ... - Página 48
por Thomas Sherwin - 1841 - 300 páginas
Vista completa - Acerca de este libro

New Elementary Algebra: Containing the Rudiments of the Science for Schools ...

Horatio Nelson Robinson - 1874 - 340 páginas
...vx=\ / — = vu , __ J у я the entire quotient, therefore, is 3av/y. Hence the following RULE. I. Divide the coefficient of the dividend by the coefficient of the divisor. II. Divide the quantity in the radical part of the dividend by the quantity in the radical part of...
Vista completa - Acerca de este libro

New University Algebra

Horatio Nelson Robinson - 1875 - 430 páginas
...principles already given we have the following RULE. — To divide one monomial by another ; — I. Divide the coefficient of the dividend by the coefficient of the divisor, for a new coefficient. II. To this result annex the letters of the dividend, with the exponent of each...
Vista completa - Acerca de este libro

New Elementary Algebra: Designed for the Use of High Schools and Academies

Benjamin Greenleaf - 1879 - 322 páginas
...obtain 2 %/a. Hence the following RULE. Seduce the radical parts, if necessary, to a common index; then divide the coefficient of the dividend by the coefficient of the divisor, and the radical part of the dividend by that of the divisor, and prefix the first quotient to the last...
Vista completa - Acerca de este libro

Sheldons' Complete Algebra: Part I Being Sheldon's Elements of ..., Partes1-2

1888 - 492 páginas
...division can also be performed without reducing the quantities to their simplest form. Thus, Rule. — Divide the co-efficient of the dividend by the co-efficient of the divisor for< the co-efficient of the quotient. EXERCISES. . Divide: 1. л/Ш) by 2л/8. 5. 24л/2 by 2л/8....
Vista completa - Acerca de este libro

The Normal Elementary Algebra: Containing the First Priniples of the Science ...

Edward Brooks - 1888 - 344 páginas
...principle above ; hence the entire quotient is — 6j/2as Sy'Sx, which, reduced, equals 6\/2x. Rule. — I. Divide the coefficient of the dividend by the coefficient of the divisor, and the radical part of the dividend by the radical part of the divinar . IL Annex the latter quotient...
Vista completa - Acerca de este libro

The Normal Elementary Algebra: Containing the First Principles of the ...

Edward Brooks - 1888 - 190 páginas
...dividing gOa56 -s- 5os - 4a26 a5 by a3, we have a* (Prin. 2). Hence the quotient is 4a26. Rule. — I. Divide the coefficient of the dividend by the coefficient of the divisor for the coefficient of the quotient. II. Write the letters of the dividend in the quotient, giving...
Vista completa - Acerca de este libro

Algebra for the Use of High Schools, Academies and Colleges

John Bernard Clarke - 1889 - 566 páginas
...divisor. As the letters employed may represent any quantities whatever, \ve deduce the following RULE. — Divide the coefficient of the dividend by the coefficient of the divisor. To this quotient annex the radical sign, under which place the quotient obtained by dividing the quantity...
Vista completa - Acerca de este libro

A School Algebra

George Albert Wentworth - 1891 - 380 páginas
...a aaaa = aaa = a = a 79. To divide one monomial by another, therefore, we have the following rule : Divide the coefficient of the dividend by the coefficient of the divisor (observing the law of signs), and subtract the index of any letter in the divisor from the ir dex of...
Vista completa - Acerca de este libro

Elements of Algebra: A Course for Grammar Schools and Beginners in Public ...

William James Milne - 1894 - 216 páginas
...term must be divided separately. KULE. Divide each term of the dividend by the divisor as follows : Divide the coefficient of the dividend by the coefficient of the divisor. To this quotient annex each literal factor of that term of the dividend with an exponent equal to the...
Vista completa - Acerca de este libro

Elements of Algebra: A Course for Grammar Schools and Beginners in Public ...

William James Milne - 1894 - 214 páginas
...term must be divided separately. RULE. Divide each term of the dividend by the divisor as follows : Divide the coefficient of the dividend by the coefficient of the divisor. To this quotient annex each literal factor of that term of the dividend with an exponent equal to the...
Vista completa - Acerca de este libro




  1. Mi biblioteca
  2. Ayuda
  3. Búsqueda avanzada de libros
  4. Descargar EPUB
  5. Descargar PDF