 | Euclid - 1845 - 218 páginas
...ACDB into two equal parts. QED BOOK I. PROP. XXXV. XXXVI. PROPOSITION XXXV. THEOR. — Parallelograms upon the same base, and between the same parallels, are equal to one another. Let the parallelograms ABCD, EBCF be upon the same See the 2nd base BC, and between the same parallels AF,... | |
 | Euclides - 1845 - 546 páginas
...divides the parallelogram ACDB into two equal parts. QED PROPOSITION XXXV. THEOREM. Parallelograms upon the same base, and between the same parallels, are equal to one another. Let the parallelograms ABCD, EBCF be upon the same base BC, and between the same parallels AF, BC. Then the... | |
 | Euclid, James Thomson - 1845 - 382 páginas
...parallelogram AC is equal (I. ax. 1) to EG. Wherefore parallelograms, &c. PROP. XXXVII. TnEOR.t — Triangles upon the same base, and between the same parallels, are equal to one another. * lt will appear, from this proposition, that the perimeters of two equal parallelograms on the same... | |
 | Euclides - 1846 - 292 páginas
...to the triangle DBC. Wherefore, Triangles %c. QED PROP. XXXVIII. THEOR. Triangles upon equal bases, and between the same parallels, are equal to one another. Let the triangles ABC, DEF be upon equal bases BC, EF, and between the same parallels BF, AD : the triangle ABC shall be equal... | |
 | London univ - 1846 - 326 páginas
...exterior angles of any rectilineal figure are together equal to four right angles. 6. Parallelograms upon the same base and between the same parallels are equal to one another. 7. Show that the complements of the parallelograms which are about the diameter of any .parallelogram... | |
 | Great Britain. Admiralty - 1846 - 128 páginas
...two = parts. Wherefore the opposite sides and angles, &c. PROP. XXXIV. THEOR. 35. lEu. Parallelograms upon the same base, and be-tween the same parallels, are equal to one another. FA DEFAEDF \ . If the sides AD, DF, of the / — 7"" ABCD, DBCF, opp. to RC the base, be terminated... | |
 | W. PEASE - 1846 - 86 páginas
...isosceles triangle required. The reason of this is (Prob. XXXVII. Bk. I. Euclid,) because triangles upon the same base, and between the same parallels, are equal to one another : ie the triangles ACB and AE B, being upon the base, AB, to which the line EC is parallel, therefore... | |
 | Euclid, John Playfair - 1846 - 334 páginas
...adjacent angles of a parallelogram is equal to two right angles. PROP. XXXV. THEOR. Parallelograms upon, the same base and between the same parallels, are equal to one another. > (SEE THE 2d AND 3d FIGURES.) 34 If the sides AD, DF of the parallelograms ABCD, DBCF opposite to... | |
 | Great Britain. Admiralty - 1846 - 128 páginas
...•=• parts. Wherefore the opposite sides and angles, &c. PROP. XXXIV. THEOR. 3s. lEu. Parallelograms upon the same base, and between the same parallels, are equal to one another. PROP. XXXIV. FADE F \ . If the sides AD, DF, of the 1=1™ ABCD, DBCF, opp. to BC the base, be terminated... | |
 | Anthony Nesbit - 1847 - 492 páginas
...parallelogram ABCD, is equal to the parallelogram DBCE. (Euc. I. 35. Simp. II. 2. Em. HI. 6.) THEOREM VL Let the triangles ABC, DBC be upon the same base BC,...BC ; the triangle ABC is equal to the triangle DBC. (Euc. I. 37. Simp. II. 2. Em. II. 10.) THEOREM VH. Let ABC be a right-angled triangle, having the right... | |
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Parallelograms upon the same base and between the same parallels, are equal to one another. 
