| Webster Wells, Walter Wilson Hart - 1912 - 344 páginas
...с — d EXAMPLE. Since — = — , then, 10 + 2 should equal 15_+-? . Does it ? 2 3 10-2 15-3 224. In a series of equal ratios, the sum of the antecedents...consequents as any antecedent is to its consequent. If 5=0 = 1, etc., prove a + c + e + etc' =°. bdf b+d+f+ete. b PROOF. 1. Let v = the common value of... | |
| William Betz, Harrison Emmett Webb - 1912 - 368 páginas
...b : d = a : c. B. d:b = c : a. 7. c: a = d:b. 4. d : c = b : a. 8. c : d = a : b. 361. Theorem IV. In a series of equal ratios the sum of the antecedents...consequents as any antecedent is to its consequent. Proof. If - = - = - = 7, let a; represent the value of each bdf li of the ratios. Then a = bx, c =... | |
| Webster Wells, Walter Wilson Hart - 1912 - 344 páginas
...— d EXAMPLE. Since — = — , then, 10 + 2 should equal 15 + 3 • Does it ? 2 3 10-2 15-3 224. In a series of equal ratios, the, sum of the antecedents...the sum of the. consequents as any antecedent is to UK consequent. If ?=«-!, etc, prove a + с + e + etc. = a. bd f' - & + d+/+ete. 6 PROOF. 1. Let v... | |
| John William Hopkins, Patrick Healy Underwood - 1912 - 362 páginas
...Y) 7. If»a :Ъ= c: d= e:f, then a + с + e : b + d+f— a: b. If a number of ratios are equal, then the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent. Let - = - = - = r, then a = br, c= dr, e =fr. oaf e br drr= .. b+d+f b+d+f •'• 1а + л + ! = Г'... | |
| Herbert Ellsworth Slaught, Nels Johann Lennes - 1912 - 300 páginas
...bk + dk+fk= (b + d+f)k, and a + c + e=fc=g = £ = g. b+d+fbdf That is, If several ratios are equal, the sum of the antecedents is to the sum of the consequents as any antecedent is to its consequent. EXERCISES 1. If ad = bc, show that - = - • Hint. Divide by bd. bd Z If ad=bc, show that- = -• 3.... | |
| Walter Burton Ford, Charles Ammerman - 1913 - 378 páginas
...c/d, to prove that (a + 6)/(« - 6) = (c+d)/(c- d). Proof. We have = . = . bdbd Th E' p Theorem H. In a series of equal ratios the sum of the antecedents...consequents as any antecedent is to its consequent. Given a/6 = c/d = e/f= —, to prove that ace Proof. Let k be the value of any one of the equal ratios... | |
| Walter Burton Ford, Earle Raymond Hedrick - 1913 - 272 páginas
...that (a + b)/(a — 6) = (c+d)/(c— d). Proof. We have a±b = c_ + d> mda^b = ed. Th. E,F Theorem H. In a series of equal ratios the sum of the antecedents...consequents as any antecedent is to its consequent. Given a/6 = c/d = e/f= —, to prove that . ace b+d+f+- bdf Proof. Let A; be the value of any one of... | |
| William Benjamin Fite - 1913 - 368 páginas
...last equation. A similar result holds for any number of equal ratios, and may be stated as follows : In a series of equal ratios the sum of the antecedents...consequents as any antecedent is to its consequent. CHAPTER XV QUADRATIC EQUATIONS 156. In § 108 the student learned how to solve certain quadratic equations,... | |
| William Benjamin Fite - 1913 - 304 páginas
...last equation. A similar result holds for any number of equal ratios, and may be stated as follows : In a series of equal ratios the sum, of the antecedents...consequents as any antecedent is to its consequent. CHAPTER XV QUADRATIC EQUATIONS 149. In § 108 the student learned how to solve certain quadratic equations,... | |
| Walter Burton Ford, Charles Ammerman - 1913 - 176 páginas
...If four quantities are in proportion, they are in proportion by composition and division. Theorem H. In a series of equal ratios the sum of the antecedents...consequents as any antecedent is to its consequent. PART II. PROPORTIONAL LINE-SEGMENTS 145. Theorem I. A line parallel to the base of a triangle divides... | |
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