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" To find the Area of a Trapezoid. RULE. Multiply half the Sum of the two parallel Sides by the perpendicular distance between them, or the sum of the two parallel Sides by half the perpendicular distance ; the Product will be the Area. "
The Carpet-dealer's Guide: A Manual of Practical Information on the Art of ... - Página 48
por John H. Macke - 1891 - 228 páginas
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The advanced lesson book, by E.T. Stevens and C. Hole

Edward Thomas Stevens - 1866 - 434 páginas
...which has only two of its opposite sides parallel, as ABD c. AE is the perpendicular. c K u To Jind the area of a trapezoid. RULE : — Multiply half the sum of the parallel sides by tho perpendicular distance between them ; the product is the area. DD THE CIRCLE....
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Elements of Plane and Solid Geometry: And of Plane and Spherical ...

Gerardus Beekman Docharty - 1867 - 474 páginas
...and 25.69 chains respectively, to find the area. Ans. 61 acres, 2 roods nearly. PROBLEM VI. Tojind the area of a trapezoid. RULE. Multiply half the sum...two parallel sides by the altitude of the trapezoid. (Geom., BI, th. 29.) Or, Multiply the altitude by the distance between the middle points of its inclined...
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University Arithmetic: Embracing the Science of Numbers, and General Rules ...

Charles Davies - 1867 - 354 páginas
...AB, DC, parallel. The perpendicular CE is called the altitude. 322. To find the area of a trapezoid. Multiply half the sum of the two parallel sides by the altitude, and the product will be the area. (Bk. IV. Prop. VII.) EXAMPLES. 1 . Required the area of the trapezoid...
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The Common School Arithmetic: Combining Analysis and Synthesis ; Adapted to ...

James Stewart Eaton - 1873 - 340 páginas
...upon it, from the other angles of the trapezium, 6 and 8 inches ? Ans. 140 sq. in. 389. PROBLEM 3. To find the area of a trapezoid : RULE. Multiply half the sum of the parallel sides by the altitude, and the product will be the area. 387. What it a Quadrilateral ? How...
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The High School Arithmetic: Containig All the Matter Usually Presented in a ...

Philotus Dean - 1874 - 472 páginas
...rd. 4. What is the area of a triangle whose sides are, respectively, 18, 20, and 24 inches? Art. 473. To find the area of a trapezoid. Rule. — Multiply half the sum of the parallel sides by the altitude. Í. How many square feet in a board 18 ft. long, 18 in. wide at one...
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Common School Arithmetic

James Stewart Eaton - 1876 - 366 páginas
...upon it, from the other anglea of the trapezium, 6 and 8 inches ? Ans. 140 sq. in. 389. PKOBLEM 3. To find the area of a trapezoid : RULE. Multiply half the sum of the parallel sides by the altitude, and the product will be the area. 387. What is a Quadrilateral ? How...
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The New American Arithmetic, Parte3

Samuel Mecutchen, George Mornton Sayre - 1877 - 200 páginas
...5. The base of a rhomboid is 375 ft. 6 in., and the perpendicular height 40 yards; what is its area? To find the area of a trapezoid. RULE. Multiply half the sum of the parallel sides by the altitude. 1. What is the number of square feet in a trapezoid, one of the parallel...
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Ray's New Higher Arithmetic: A Revised Edition of the Higher Arithmetic

Joseph Ray - 1880 - 420 páginas
...II. To find the area of a triangle. Rule.— Take half the product of the base by the altitude. III. To find the area of a trapezoid. Rule. — Multiply half the sum of the parallel sides by the altitude. NOTE. — The following is demonstrated in Geometry : IV. To find the...
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Mensuration for beginners [With] Answers

William Dodds - 1883 - 198 páginas
...area of a trapezoid when the parallel sides and the perpendicular distance between them are given. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them, and the product will be the area. If two straight "iT lines are...
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Caldwell's Practical Arithmetic ...

M. P. Caldwell - 1883 - 198 páginas
...garden whose area is J an acre; it is 110 yards long; how wide is it? Ans. 22 yds. PROPOSITION 5.— To find the area of a trapezoid. RULE. — Multiply half the sum of the parallel sides by the altitude, and the product is the area. Or, place the altitude and half the sum...
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