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" The opposite angles of a quadrilateral inscribed in a circle are together equal to two right angles, with converse. "
Proceedings of the Edinburgh Mathematical Society - Página 11
por Edinburgh Mathematical Society - 1894
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Numerical Problems in Plane Geometry: With Metric and Logarithmic Tables

Joe Garner Estill - 1896 - 186 páginas
...polygon. Prove that every equiangular polygon circumscribed about a circle is a regular polygon. 5. Prove that the opposite angles of a quadrilateral inscribed in a circle are supplements of each other. 6. Construct a square, having given its diagonal. 7. Prove that the area...
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Numerical Problems in Plane Geometry: With Metric and Logarithmic Tables

Joe Garner Estill - 1896 - 214 páginas
...polygon. Prove that every equiangular polygon circumscribed about a circle is a regular polygon. 5. Prove that the opposite angles of a quadrilateral inscribed in a circle are supplements of each other. 6. Construct a square, having given its diagonal. 7. Prove that the area...
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Annual Report of the Commissioners ..., Volumen64

1898 - 830 páginas
...perpendiculars from the angles of a triangle to the opposite sides meet in a point (4 marks). 2. Prove that the opposite angles of a quadrilateral inscribed in a circle are equal to two right angles (10 marks). Show also that if a circle be inscribed in this quadrilateral...
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Plane and Solid Geometry: Inductive Method

Arthur A. Dodd, B. Thomas Chace - 1898 - 468 páginas
...polygon. Prove that every equiangular polygon circumscribed about a circle is a regular polygon. 5. Prove that the opposite angles of a quadrilateral inscribed in a circle are supplements of each other. 6. Construct a square, having given its diagonal. 7. Prove that the area...
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Report of the Committee of Council on Education in Scotland...[without Appendix]

1900 - 898 páginas
...part of it produced beyond the obtuse angle to meet a perpendicular from the opposite vertex. 16. 7. The opposite angles of a quadrilateral inscribed in a circle are together equal to two right angles. Two circles have a common chord AB, and from A straight lines APQ, АП8 are drawn cutting the circles...
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A Text-book of Euclid's Elements for the Use of Schools. Books I ..., Libro 1

Euclid, Henry Sinclair Hall, Frederick Haller Stevens - 1900 - 330 páginas
...with equal vertical angles is an arc of a circle. PKOPOSITION 22. THEOREM. The opposite angles of any quadrilateral inscribed in a circle are together equal to two right angles. Let ABCD be a quadrilateral inscribed in the 0 ABC. Then shall (i) the L? ADC, ABC together = two rt....
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Annual Report

Canada. Department of the Interior - 1900 - 564 páginas
...triangle the square on the hypotenuse is equali 17 to the sum of the squares on the other two sides. i 3. The opposite angles of a quadrilateral inscribed in a circle are together' 17 equal to two right angles. 42 iii 64 VICTORIA, A. 1901 4. Construct an isosceles triangle having...
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Woolwich Mathematical Papers for Admission Into the Royal Military Academy ...

Eldred John Brooksmith - 1901 - 368 páginas
...is at right angles to the diameter of the circle through its point of contact. 7. Show that any two opposite angles of a quadrilateral inscribed in a circle are together equal to two right angles. Show that two opposite sides of a convex quadrilateral (ie , a quadrilateral without re.entrant angles)...
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Massachusetts State Normal Schools: Containing a Circular of Information, a ...

1901 - 258 páginas
...ABC and DEF are mutually equiangular. Prove that they are similar. Take eit)tcr 5 or &• 5. Prove that the opposite angles of a quadrilateral inscribed in a circle are supplementary. 6. Let there be a regular inscribed polygon whose number of sides is indefinitely increased....
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Annual Report of the Commissioners ..., Volumen68

1902 - 482 páginas
...another in only one point, . whether it touch it internally or externally. 4. The opposite angles of any quadrilateral inscribed in a circle are together equal to two right angles. 6. Inscribe a circle in a regular pentagon. 6. Describe a circle about a given triangle. SECTION B....
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