CD, &c., taken together, make up the perimeter of the prism's base : hence the sum of these rectangles, or the convex surface of the prism, is equal to the perimeter of its base multiplied by its altitude. Elements of Geometry - Página 182por Adrien Marie Legendre - 1841 - 235 páginasVista completa - Acerca de este libro
| Charles Davies, Adrien Marie Legendre - 1885 - 538 páginas
...and the area of each rectangle is equal to its base multiplied by its altitude (B. IV., PV) : hence, the sum of these rectangles, or the convex surface of the prism, is equal to, (AB + BC + CD + DE + EA) x AF ; that is, to the perimeter of the base multiplied by the altitude ;... | |
| Charles Davies - 1886 - 352 páginas
...distance be J ween the parallel planes which form its bases THEOREM I. The convex surface of a right prism is equal to the perimeter of its base multiplied by its altitude. Let ABCDE—K be a right prism : then will its convex surface be equal to (AB.) BC+CD+DE+EA)xAF. For,... | |
| Webster Wells - 1886 - 392 páginas
...Whence by § 195, S = PxE. 704. COROLLARY I. The lateral area of a cylinder of revolution (§ 597) is equal to the perimeter of its base multiplied by its altitude. 705. COROLLARY II. If S denotes the lateral area, H the altitude, and R the radius of the base of a... | |
| Webster Wells - 1886 - 166 páginas
...= DE X AA' + EF X AA' + etc. = (DE + EF + etc.) X AA'. 521. COROLLARY. The lateral area of a right prism is equal to the perimeter of its base multiplied by its altitude: PROPOSITION III. THEOREM. 522. Two prisms are equal when the faces including a triedral angle of one... | |
| Webster Wells - 1893 - 390 páginas
...any text-book on Solid Geometry: 1. The lateral area of a right prism (or rectangular parallelopiped) is equal to the perimeter of its base multiplied by its altitude. 2. The volume of a prism (or rectangular parallelopiped) is equal to the area of its base multiplied... | |
| Jared Sparks, Edward Everett, James Russell Lowell, Henry Cabot Lodge - 1828 - 620 páginas
...its altitude. Now it has already been demonstrated, lemma 620, that ' the convex surface of a right prism, is equal to the perimeter of its base multiplied by its altitude.' Admitting, then, our principle, the convex surface of a cylinder will consist of an infinite number... | |
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