 | Nicolas Pike, Dudley Leavitt - 1826 - 214 páginas
...two or more numbers. RULE 1. If there be two pumbers only, divide the greater by the less, and this divisor by the remainder, and so on, always dividing...the last divisor by the last remainder, till nothing remain ; then will the last divisor be the greatest common measure required. 2. When there are more... | |
 | Nicolas Pike, Dudley Leavitt - 1826 - 222 páginas
...two or more numbers. RULE 1. If there be two numbers only, divide Jhe greater by the less, and this divisor by the remainder, and so on,, always dividing...the last divisor by the last remainder, till nothing remain ; tben will the last divisor be the greatest common measure required. 2. When there are more... | |
 | Daniel Adams - 1848 - 322 páginas
...greatest common measure of two numbers, RULE. Divide the greater number by the less, and that divrsor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. NOTE 1. — When we would find... | |
 | James Ryan - 1827 - 290 páginas
...to the other, problems VII. &c. If there be a remainder, divide the less by it ; and thug proceed, always dividing the last divisor by the last remainder, till nothing remains. The divisor which leaves no remainder, is the common measure required. If the divisor which leaves DO remainder... | |
 | Daniel Adams - 1828 - 286 páginas
...greater than 32, can do it. Hence the ride for fmding the greatest common divisor of two numbers : — Divide the greater number by the less, and that divisor...the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
 | Daniel Adams - 1828 - 266 páginas
...rule for finding the greatest common divisor of two numbers : — Divide, the greater number by tbe less, and that divisor by the remainder, and so on,...the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
 | Nathan Daboll - 1828 - 250 páginas
...lowest teraist Ki;r,r. — 1. Find a common measure, by dividing the greater tenp by the less, and this divisor by the remainder, and so on, always di•viding...divisor by the last remainder, till nothing remains; (be last divisor is the common measure.* 2. Divide both of the terms of the fraction by the common... | |
 | Nathan Daboll - 1828 - 268 páginas
...a common measure, by dividing the greater term by the less, and this divisor by the remainder, ami so on, always dividing the last divisor by the last remainder, till nothing remams, the last divisor is the common measure.* 2. Divide both of the terms of the fraction by the... | |
 | Nathan Daboll - 1829 - 252 páginas
...common measure, by dividing the greater term by the Ions, and this divisor by the remainder, and pn on, always dividing the last divisor by the last remainder, till nothing remaini', the last divisor is the common measure.* 2. Divide both of the terms of the fraction by the... | |
 | Daniel Adams - 1830 - 268 páginas
...greater than 32, can do it. Hence the rule for finding the greatest common divisor of two numbers : — Divide the greater number by the less, and that divisor...the last divisor by the last remainder, till nothing remain. The last divisor will be the greatest common divisor required. Note. It is evident, that, when... | |
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Find a common measure, by dividing the greater term by the less, and this divisor by the remainder, and so on, always dividing the last divisor by the last remainder, till nothing remains; the last divisor is the common measure.* 2. Divide both of the... 
