 | Euclides - 1816 - 588 páginas
...AC, and twice the rectangle CB, BD, that is, the square of AC alone is less than the squares of CB, BA by twice the rectangle CB, BD. Secondly, Let AD...ABC: Then, because the angle at D is a right angle, * 16. 1. the angle ACB is greater'1 than a right angle ; and therefore the «12.2. squ.ire of AB is... | |
 | John Playfair - 1819 - 354 páginas
...less *han BC3 + AB3 bv 2BC.BD. , Secondly, Let AD fall without Be. triangle ABC* : Then because fche angle at D is a right angle, the angle ACB is greater (16. I.) than A right angle, Snd AB3= (12. 2.) AC3+BC3+2BC.CD. Add BC3 to each ; then AB3+BC3 — ACs+... | |
 | Euclid, Robert Simson - 1821 - 514 páginas
...AC, and twice the rectangle CB, BD, that is, the square of AC alone is less than the squares of CB, BA by twice the rectangle CB, BD. Secondly, Let AD...the triangle ABC: then, because the angle at D is aright angle, the angle ACB is greater (16. 1.) than a right angle; and therefore the square of AB... | |
 | Peter Nicholson - 1825 - 1046 páginas
...AC, and twice the rectangle CB, BD, that is, the square of AC alone a lets than the squares of CB, BA by twice the rectangle CB, BD. Secondly, Let AD...angle at D, is a right angle, the angle ACB is greater (16. 1.) than a right angle ; and therefore the square of AB is equal (12.2.) to the squares of AC,... | |
 | Euclid, John Playfair - 1826 - 326 páginas
...is less than BC3+AB3 by 2BC.BD. . 4- Seeondly, Let AD fall without the triangle ABC* : Then beeause the angle at D is a right angle, the angle ACB is greater (16. 1.) than a right angle, and AB3=('l2. 2.) AC3+BC3+2BC.CD. Add BCa to eaeh; then AB3+BC3=AC3+2BC3+2BC.CD.... | |
 | Robert Simson - 1827 - 546 páginas
...AC, and twice the rectangle CB, BD ; that is, the square of AC alone is less than the squares of CB, BA, by twice the rectangle CB, BD. Secondly, let AD fall without the A triangle ABC: then, because the angle at D is a right angle, the angle ACB * 16. 1. is greater* than... | |
 | Euclid, Robert Simson - 1829 - 548 páginas
...AC, and twice the rectangle CB, BD, that is, the square of AC alone is less than the squares of CB, BA by twice the rectangle CB, BD. Secondly, Let AD fall without the A triangle ABC : then, because the angle at D is a right angle, the angle ACB is greater (16. 1.) than... | |
 | John Playfair - 1832 - 358 páginas
...DA" = AC" (47. 1.); therefore BC» + AB* = 2BC. BD+AC'; that is, AC* is less than JBC'+AB' by 2BC.BD. Secondly, Let AD fall without the triangle ABC:* Then...angle at D is a right angle, the angle ACB is greater (16. l.Jthan aright angle, and AB'= (12. 2.) A<>+BC»+2BC CD. AddBC* to each: then AB +BC =AC + 2BC... | |
 | Euclides - 1834 - 518 páginas
...AC, and twice the rectangle CB, BD ; that is, the square of AC alone, is less than the squares of CB, BA, by twice the rectangle CB, BD. Secondly, let AD...the angle at D is a right angle, the angle ACB is 1 3. 2. BOOK iI. PROP. xiv. AB is equal* to the squares of AC, CB, and twice the rectangle * 12. 2.... | |
 | Robert Simson - 1835 - 544 páginas
...rectangle CB, BD, that is, the square of AC alone is less..-- ._ • than the squares of CB, BA, by _t> ±J twice the rectangle CB, BD. Secondly, Let AD fall...angle at D is a right angle, the angle ACB is greater d than a right angle ; and therefore the square of AB is equal r to the squares of AC, CB, and twice... | |
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CB, BA, by twice the rectangle CB, BD. Secondly, Let AD fall without the triangle ABC. Then, because the angle at D is a right angle, the angle ACB is greater than a right angle ; (i. 
