 | Horatio Nelson Robinson - 1854 - 306 páginas
...period, and set its root on the right of the given number; subtract said square from the left-hand period, and to the remainder bring down the next period...a dividual. 3. Double the root for a divisor, and fry how often this divisor (with the figure used in the trial thereto annexed) is contained in the... | |
 | James Gray - 1854 - 120 páginas
...root of that number as the first figure of the root sought : subtract the number itself from the said period, and to the remainder bring down the next period for a dividend. 3. Find a divisor by multiplying the square of the part of the root found by 300, divide... | |
 | Dana Pond Colburn - 1855 - 396 páginas
...place its root as the highest denomination of the required root. Third. Subtract the square thus found from the left hand period, and to the remainder bring down the next period, calling the result a dividend. Fourth. Double the part of the root already found for a trial divisor.... | |
 | Charles Davies, William Guy Peck - 1855 - 628 páginas
...and place its cube root on the right, after the manner of a quotient in division. Subtract this cube from the left hand period, and to the remainder bring down the first figure of the next period and call this number the dividend. Take three times the square of the... | |
 | Benjamin Peirce - 1855 - 308 páginas
...and its root is the left hand figure of the required root. Subtract the square of the root thus found from the left hand period, and to the remainder bring down the second period "for a dividend. Double the root for a divisor, and the quotient of the dividend exclusive... | |
 | Dana Pond Colburn - 1856 - 392 páginas
...hand period, and place its root as the first figure of the required root. Third. Subtract this cube from the left hand period, and to the remainder bring down the next period, calling the result a dividend. Fourth. Find three times the square of the part of the root already... | |
 | Roswell Chamberlain Smith - 1856 - 334 páginas
...last period on the left, write its root on the right, as a quotient, subtract the square from the said period, and to the remainder bring down the next period for a dividend. 16. Double the root (quotient) for a partial divisor, and on its right, place, for the total... | |
 | Charles Guilford Burnham - 1857 - 328 páginas
...the left-hand period, and place its root as a quotient in division. III. Subtract the cube from said period, and to the remainder bring down the next period, for a dividend. IV. Multiply the square of the quotient by 300, calling it the triple square, and the, quotient... | |
 | Joseph Ray - 1857 - 348 páginas
...its root on the right. like a quotient in division. Subtract the square of this root from the left period, and to the remainder bring down the next period for a dividend. 3. Double the .root found, and place it on the left for a trial divisor. Find how many times... | |
 | Benjamin Greenleaf - 1857 - 336 páginas
...the left-hand period, and place its root on • the right. Subtract the cube, thus found, from this period, and to the remainder bring down the next period for a dividend. Multiply the square of the root already found by ZOO for a divisor, by which divide the dividend,... | |
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Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. 
