| Elias Loomis - 1855 - 178 páginas
...AC=299.6. In this example there is no ambiguity, because the given angle is obtuse. CASE III. (55.) **Given two sides and the included angle, to find the third side** and the remaining angles. The sum of the required angles is found by subtracting the given angle from... | |
| John Hymers - 1858
...suppose, and the colatitudes PA = b, PB = a, are known ; so that in the spherical triangle APB there are **given two sides and the included angle to find the third side** AB = c, which may be done by the formula of Art. 43, л , ^ cos a cos Ф — 0) tan в = tan a cos... | |
| Henry William Jeans - 1858
...find from the tables. RULE IX. — THIRD METHOD (REQUIRING ONLY THE COMMON TABLE OF SINES, «fee.). **Given two sides and the included angle, to find the third side.** Take the difference. between the two given sides: divide it by 2, and thus get -half the difference... | |
| ELIAS LOOMIS, LL.D. - 1859
...AC=299.6. In this example there is no ambiguity, because the giver* angle is obtuse. CASE III. (55.) **Given two sides and the included angle, to find the third side** and the remaining angles. The sum of the required angles is found by subtracting the given angle from... | |
| Frederick Robert A. Glover - 1859
...accomplished by one operation instead of two. The first case has already been considered. The second case is, **Given two sides and the included angle to find the third side** and remaining angle. The required side must be first sought. The instrument must be opened to shew... | |
| Elias Loomis - 1871 - 58 páginas
...AC=299.6. In this example there is no ambiguity, because the givet angle is obtuse. CASE III. (55.) **Given two sides and the included angle, to find the third side** and the remaining' angles. The sum of the required angles is found by subtracting the given angle from... | |
| Henry W. Jeans - 1872
...sin. 0 [2] [1] and [2], in words, are Eule IV. First Method. (87.*) Proof of Rule IV. Second Method. **Given two sides and the included angle, to find the third side.** Since 2 be . cos. A=us+c" — a2 * — 2 ¿i« . cos. A L —cos. A) =(b—cf + Ш . sin.2Á- (a) Again,... | |
| Henry William Jeans - 1873
...10-574359 log. sin. . 9-985104 log. &... 1-589255 &=38-84 EULE IV. — SECOND METHOD, WITHOUT HAVERSINES. **Given two sides and the included angle, to find the third side.** Add together the two given sides, and also subtract them : thus find their sum and difference. Put... | |
| William Kent - 1907 - 1129 páginas
...by subtracting the sum of the other two from 180", and the third side is found as in Case I. CASK m. **Given two sides and the included angle, to find the third side** and the remaining angles. The sum of the required angles is found by subtracting the given angle from... | |
| William Kent - 1923 - 2247 páginas
...180°- (38° 30' + 53° 6') = 88° 24'. C = a sin С -5- sin A = 27X0.9996-5-0.6225 = 43.35. CASE III. **Given two sides and the included angle, to find the third side** ,nd the remaining angle. Given sides a and ft and angle C. A + B = 180° — C. From Theorem II, (a... | |
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