 | Jeremiah Day - 1835 - 356 páginas
...the last term of the square of any binomial quantity, is equal to the square of half the co-efficient of the root of the first term. From this principle...the following rule : 305. To COMPLETE THE SQUARE in mi affected quadratic equation: TAKE THE SQUARE OF HALF THE CO-EFFICIENT or THE FIRST POWER OF THE... | |
 | 1836 - 488 páginas
...unknown quantity in one term, and the square of that quantity in another term. To complete the square of an affected quadratic equation, take the square of...quantity, and add it to both sides of the equation. After the square is completed, the equation is reduced, by extracting the square root of both sides,... | |
 | James Bates Thomson - 1844 - 266 páginas
...the first term. 257. From this principle is derived the following METHOD FOR COMPLETING THE SQUARE. Take the square of half the co-efficient of the first...quantity, and add it to both sides of the equation. 258. It will be observed that there is nothing peculiar in the solution of affected quadratics, except... | |
 | Davis Wasgatt Clark - 1844 - 394 páginas
...first, second, third, or fourth power, the first member may be rendered a perfect square by adding the square of half the coefficient of the first power of the unknown quantity to both members of the equation. This is called completing the square. 326. Each of the above equations... | |
 | Davis Wasgatt Clark - 1846 - 374 páginas
...first, second, third, or fourth power, the first member may be rendered a perfect square by adding the square of half the coefficient of the first power of the unknown quantity to both members of the equation. This is called completing the square. 326. Each of the above equations... | |
 | Jeremiah Day - 1847 - 358 páginas
...the last term of the square of any binomial quantity, is equal to the square of half the co-efficient of the root of the first term. From this principle...equation : TAKE THE SQUARE OF HALF THE CO-EFFICIENT or THE FIRST POWER OF THE UNKNOWN QUANTITY, AND ADD *T TO BOTH SIDES OF THE EQUATION. by transposition... | |
 | Jeremiah Day - 1848 - 354 páginas
...the last term of the square of any binomial quantity, is equal to the square of half the co-efficient of the root of the first term. From this principle...the square, the known and unknown quantities must he brought on opposite sides of the equation by transposition ; and the highest power of the unknown... | |
 | Jeremiah Day - 1848 - 356 páginas
...the last term of the square of any binomial quantity, is equal to the square of half the co-efficient of the root of the first term. From this principle...in an affected quadratic equation: TAKE THE SQUARE OP HALF THE CO-EFFICIENT OF THE FIRST POWER OF THE UNKNOWN QUANTITY, AND ADD IT TO BOTH SIDES OF THE... | |
 | Jeremiah Day, James Bates Thomson - 1848 - 264 páginas
...the first term. 257. From this principle is derived the following METHOD FOR COMPLETING THE SQUARE. Take the square of half the co-efficient of the first...quantity, and add it to both sides of the equation. 258. It will be observed that there is nothing peculiar in the solution of affected quadratics, except... | |
 | Jeremiah Day - 1849 - 350 páginas
...COMPLETE THE SQUARE in an affected quadratic equation: TAKE THE SQUARE OP HALF THE CO-EFFICIENT or THE FIRST POWER OF THE UNKNOWN QUANTITY, AND ADD IT...Before completing the square, the known and unknown quant ii ies must be brought on opposite sides of the equation by transposition ; and the highest power... | |
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In the same manner, it may be proved, that the last term of the square of any binomial quantity, is equal to the square of half the co-elficient of the root of the first term. 
