| Her MAjesty' Inspectors of schools - 1850
...and duplicate ratio. 3. Solve Euc. II. 11. To divide a given finite straight line into two part*, so **that the rectangle contained by the whole and one of the parts** may be equal to the square of the other jjart. '2. Prove Kuc. 1. 36. Parallelograms upon equal bases,... | |
| Harvey Goodwin - 1851 - 173 páginas
...equations, or any demonstration other than Euclid's ? 3. Divide a given straight line into two parts, so **that the rectangle contained by the whole and one of the parts** shall be equal to the square of the other part. Shew that in Euclid's figure four other lines, beside... | |
| 77 - 1851
...twice the rectangle contained by the parts. 5. To divide a given straight line into two parts, such **that the rectangle contained by the whole and one of the parts** shall be equal to the square of the other part. 6. If two circles cut one another they cannot have... | |
| FRANCIS J. JAMESON - 1851
...4BC2 + AB2 + AC2, = 4BC2 + BC2, - 5BC8. 1849. (A). Divide a given straight line into two parts, so **that the rectangle contained by the whole and one of the parts** shall be equal to the square of the other part. (ii. 11.) (B). Shew that in Euclid's figure, four other... | |
| ...Book 1 and state what ease is omitted. SECTION IT. 1. Divide a given straight line into two parts, so **that the rectangle contained by the whole and one of the parts,** shall be equal to the square of the other part. 2. If a straight line be divided into any two parts,... | |
| Euclides - 1852
...the other part. Let AB be the given straight line ; it is required to divide it into two parts, so **that the rectangle contained by the whole, and one of the parts,** shall be equal to the square of the other part. Upon AB describe* the square ABDC; • x hi. i. bisect*... | |
| Bengal council of educ - 1852
...proposition included in any more general one ? (2.) To divide a given straight line into two parts, so **that the rectangle contained by the whole and one of the parts,** shall be equal to the square of the other part. Can this be solved arithmetically ? if so, find approximately... | |
| Charles Astor Bristed - 1852
...every triangle are equal to two right angles. 3. Divide a given straight line into two such parts, **that the rectangle contained by the whole and one of the parts** shall be equal to the square of the other part. 4. The angle at the centre of a circle is double of... | |
| Euclides - 1853 - 147 páginas
...the other part. LET ab be the given straight line ; it is required to divide it into two parts, so **that the rectangle contained by the whole and one of the parts** shall be equal to the square of the other part. Upon ab describe (i. 46) the square abdС; bisect (i.... | |
| Euclides - 1853
...the other part. Let AB be the given straight line ; it is required to divide it into two parts, so **that the rectangle contained by the whole and one of the parts,** shall be equal to the square of the other part. Upon AB describe (1. 46.) the square ABDC ; bisect... | |
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