 | University of Oxford - 1879 - 414 páginas
...also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. 7. In a circle the angle in a semicircle is a right angle ; but the angle in a segment... | |
 | Moffatt and Paige - 1879 - 506 páginas
...into two unequal parts ; the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. Let the straight line AB be divided into two equal parts in the point C, and into... | |
 | Moffatt and Paige - 1879 - 378 páginas
...also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. By the 41st proposition of the first book, which proves that " if a parallelogram... | |
 | Oxford univ, local exams - 1880 - 396 páginas
...straight line. 3. If a straight line is divided into two equal parts and also into two unequal parts, the rectangle contained by the unequal parts, together...section, is equal to the square of half the line. 4. If a straight line fall upon two parallel straight lines, it makes the alternate angles equal to... | |
 | Pupil teachers - 1880 - 1486 páginas
...point of AB. 5.If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together...section, is equal to the square of half the line. The difference between the squares on any two straight lines is equal to the rectangle contained by... | |
 | Elizabethan club - 1880 - 156 páginas
...and also two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. If O be a point in the base BC (or BC produced) of the isosceles triangle ABC, the... | |
 | Sandhurst roy. military coll - 1880 - 68 páginas
...also into two unequal parts, the rectangle contained by the unequal parts together with the square on the line between the points of section is equal to the square on half the line. State and explain Euclid's corollary to this proposition. 2. In obtuse-angled triangles,... | |
 | James Russell Soley - 1880 - 346 páginas
...also into two unequal parts, the rectangle Contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. Prove that the area of a square is greater than the area of a rectangle of the same... | |
 | Great Britain. Civil Service Commission - 1880 - 670 páginas
...also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. If О be any point on the base BC (or that base produced) of the isosceles triangle... | |
 | Euclides, Frederick Burn Harvey - 1880 - 178 páginas
...oho into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line. Let AB be a straight line divided into two equal parts in C, and into two unequal... | |
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If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line. 
