 | Euclides - 1834 - 518 páginas
...Again, because the angle at B is half a right angle, and FOB •29.1. a right angle, for it is equal* to the interior and opposite angle ECB, the remaining...the angle at B is equal to the angle BFD, and the • 6. 1• side DF to * the side DB. And because AC is equal to CE, the square of AC is equal to the... | |
 | Euclid - 1835 - 540 páginas
...side GF: Again, because the angle at B is half a right angle, and FDB a right angle, for it is equal6 to the interior and opposite angle ECB, the remaining...at B is equal to the angle BFD, and the side DF to f the side DB : And because AC is equal to CE, the square of AC is equal to the square of CE ; therefore... | |
 | John Playfair - 1837 - 332 páginas
...angle GEF is half a right angle, and EGF a right angle, for it is equal (29. 1.) to the interior and opposite angle ECB, the remaining angle EFG is half...EF2=EG2+GF2; therefore, EF2=2GF2 =2CD2, because (34. 1.) CD=GF. And it was shown that AE2=2AC2 ; therefore AE2+EF2=2AC2+2CD3. But (47. 1.) AF2=AE2+ EF2,... | |
 | Andrew Bell - 1837 - 290 páginas
...(I. 6). Again, because the angle at B is half a right angle, and FDB a right angle, for it is equal to the interior and opposite angle ECB, the remaining...at B is equal to the angle BFD, and the side DF to the side DB. Now, because AC is equal to CE, the square of AC is equal to the square of CE ; therefore... | |
 | Euclid - 1838 - 470 páginas
...EG equal (6. 1.) to the side GF: again, because the angle at B is half a right angle, and FDB half a right angle, for it is equal (29. 1.) to the interior...angle BFD, and the side DF to (6. 1.) the side DB: and because AC is equal to CE, the square of AC is equal to the square of CE ; therefore the squares... | |
 | Robert Simson - 1838 - 434 páginas
...right angle, for it is equal (29. 1.) to the interior and opposite angle ECB, the remaining angle BFDis half a right angle ; therefore the angle at B is equal...angle BFD, and the side DF to (6. 1.) the side DB: and because AC is equal to CE, the square of AC is equal to the square of CE ; therefore the squares... | |
 | Euclides - 1838 - 264 páginas
...Again, because the angle at B is half a right angle, and *29. i. FDB a right angle, for it is equal* to the interior and opposite angle ECB, the remaining...is half a right angle : therefore the angle at B is *6. i. equal to the angle BFD, and the side DF to* the side DB. And because AC is equal to CE, the... | |
 | Euclides - 1841 - 378 páginas
...FDB a right angle, for it is * 29. 1. equal* to the interior and opposite angle ECB, theretherefore the angle at B is equal to the angle BFD, and the side DF to* the side DB. And because AC * 6 - 1. is equal to CE, the square of AC is equal to the square of CE;... | |
 | John Playfair - 1842 - 332 páginas
...angle GEF is half a right angle, and EGF a right angle, for it is equal (29. 1.) to the interior and opposite angle ECB, the remaining angle EFG is half...1.)CD=GF. And it was shown that AE2=2AC2; therefore AE2+EF2=2AC2+2CD2. But (47. 1.) AF2=AE2+EF2, and AD2+DF2= AF2, or AD2+DB2=AF2 ; therefore, also, AD2-f-DB2=... | |
 | Euclides - 1842 - 316 páginas
...equal to the angle EFG, and the side EG equal (6.1.) to the side GF. Again: because the angle at в is half a right angle, and FDB a right angle, for...BFD is half a right angle ; therefore the angle at в is equal to the angle BFD, and the side DF (6. 1.) to the side DB: and because AC is equal to CE,... | |
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Again, because the angle at B is half a right angle, and FDB a right angle, for it is equal... 
