| Euclides - 1853
...X. PROBLEM. To bisect a given finite straight line, that is, to divide it into two equal parts. Let **AB be the given straight line ; it is required to divide it into two** equal parts. Describe (I. 1.) upon it an equilateral triangle ABC, and bisect (I. 9.) the angle ACB... | |
| Euclides - 1853
...contained by the whole line and one of the parts shall be equal to the square of the other part. Let **AB be the given straight line. It is required to divide it into two** such parts, that the rectangle contained by the whole line and one of the parts shall be equal to the... | |
| Royal Military Academy, Woolwich - 1853
...PROPOSITION X. PROB. To bisect a given finite straight line, that is, to divide it into two equal parts. Let **AB be the given straight line; it is required to divide it into two** equal parts. Describe (1. i.) upon it an equilateral triangle ABC, and bisect (9. i.) the angle ACB... | |
| Euclides - 1853 - 147 páginas
...— PROBLEM. To bisect a given finite straight line, that is, to divide it into two equal parts. LET **ab be the given straight line, it is required to divide it into two** equal parts. Describe (i. 1) upon ab an equilateral triangle abc, and bisect (i. 9) the angle acb by... | |
| Cambridge univ, exam. papers - 1854
...KBD. 2. Divide a given straight line into two parts so that the rectangle contained by the whole line **and one of the parts shall be equal to the square of the other part.** Produce a given straight line to a point such that the rectangle contained by the whole line thus produced... | |
| William Walton, Charles Frederick Mackenzie - 1854 - 225 páginas
...KBD. 2. Divide a given straight line into two parts so that the rectangle contained by the whole line **and one of the parts shall be equal to the square of the other part.** Produce a given straight line to a point such that the rectangle contained by the whole line thus produced... | |
| William Somerville Orr - 1854
...the remarks at the end of this book. PROPOSITION XI.— PROBLEM. To divide a given straight line (AB) **into two parts, so that the rectangle contained by the whole, and** от of the parts, shall be equal to the square of the other part. From A draw AC perpendicular and... | |
| Great Britain. Committee on Education - 1855
...two sides of it, the angle contained by those two sides is a right angle. 3. Divide a straight line **into two parts, so that the rectangle contained by...parts shall be equal to the square of the other part.** Section 3. 1. The angles in the same segment of a circle are equal. 2. If from a point without a circle... | |
| Robert Potts - 1855
...two equal parts. Prove also that the two diameters bisect each other. 3. Divide a given straight line **into two parts, so that the rectangle contained by...parts, shall be equal to the square of the other part** Solve the same problem algebraically, and give the geometrical interpretation of the result. 4. The... | |
| Euclides - 1855
...PROBLEM. To bisect a given finite straight line. ; thai is, to divide it into two equal parts. Let **AB be the given straight line. It is required to divide it into two** equal parts. Describe upon AB (I. 1) au equilateral triangle ABC, and bisect (I. 9) the angle ACB by... | |
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